4 adult tickets were sold and 8 student tickets were sold.
How did I get this?
First, let's see what information is given:
12 tickets sold
(S)tudent ticket = $9
(A)dult ticket = $12
Total cost = $120
So, we know student tickets plus adult tickets total up to $12. We can create an equation out of this: S + A = 12
And we know $9S + $12A = $120
The variables represent the amount of tickets sold, which is unknown.
A = 12 - S , substitute this into the second equation.
9s + 12(12-s) = 120
Distribute the 12 into the parenthesis.
9s + 144 - 12s = 120
Combine like terms
-3s + 144 = 120
Subtract both sides by 144, left side cancels out.
-3s = -24
s = -24/-3
s = 8
So, 8 student tickets were sold. Plug the value of s into our first equation.
A = 12 - 8
A = 4 (adult tickets)
Answer:
think its x=3 hope it helps
Answer:
10 and 15, 20 and 25, and 35 and 45.
Step-by-step explanation:
Answer: 8 + x = 3
To solve for this, we need to get x by itself on one side of the equation.
Currently, we have 8 being added to x, so we need to perform the opposite order of equations to get rid of 8.
The opposite of +8 is -8, so subtract 8.
Remember, if you add, subract, multiply or divide by any new number, you must do it to both sides of the equation.
8 + x = 3
Subtract 8 from both sides.
8 - 8 = 0
3 - 8 = -5
We're now left with:
x = -5
Your answer is A.) -5.
I hope this helps! can u pls give me brainliest
Step-by-step explanation:
