Answer:
EF = 20 cm
Step-by-step explanation:
Here, we want to find the length of EF
To do this, we use the principle of similar triangles
The similar triangles we are considering here will be ;
FEA and FBD
when two triangles are similar, the ratio of their corresponding sides are equal
Let us calculate DC first
we can use Pythagoras’ theorem here and it is that the square of the hypotenuse equals the sum of the square of the two other sides
Using the triangle EDC
15^2 = 12^2 + DC^2
DC^2 = 225-144
DC^2 = 81
DC = 9
So the entire length of BD is 9 + 12 = 21 cm
Thus, we have it that;
Let EF be x
so DF = 15 + x
Hence;
BD/DF = AE/EF
21/15+x = 12/x
21x = 12(15 + x)
21x = 180 + 12x
21x-12x = 180
9x = 180
x = 180/9
x = 20 cm
EF = 20 cm
Answer:
c ln (x^3/y^3)
Step-by-step explanation:
3 ln x - 3 lny
We know that a ln b = ln b^a
ln x^3 - ln y^3
We also know ln a - ln b = ln (a/b)
ln (x^3/y^3)
Answer: D, When the constants are perfect squares.
Step-by-step explanation:
the “best” method whenever the quadratic equation only contains x2 terms. That implies no presence of any x term being raised to the first power somewhere in the equation.
Hopefully this helps!
Answer:
Step-by-step explanation:
If AB is parallel to CD and there is a transversal cutting through both (as there is, although it is not named here), then by the definition of corresponding angles, angles 1 and 5 are corresponding and are therefore, congruent. If angle 1 measures 120 then so does angle 5. Learn these...they're very important and are prevalent in triangle stuff in geometry!!!
Answer:
I think it's 0.648
Step-by-step explanation:
10% of 4% of 162 = 0.648
