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Elina [12.6K]
3 years ago
5

What do you think is going to be the most challenging part of Alg.1 and why?

Mathematics
2 answers:
Llana [10]3 years ago
8 0

Answer:

I think Factoring is going to be the most challenging part of Alg.1 because it seems like there are a lot of steps before finding the answers.

Blizzard [7]3 years ago
8 0

Explanation:

When I took algebra I, the most difficult part for me was inequalities.

I had been used to linear equations and even quadratic equations, where the operative rule is "keep the equal sign sacred" (whatever you do to one side must also be done to the other side). Once I figured out that multiplying or dividing inequalities by a negative number reverses the comparison, I was good to go.

__

These days, algebra I also includes a good dose of statistics. That seems to trip up a number of people, including me. The main thing, I think, is to stay clear on the definitions, and whether you're talking about a population or a sample. A lot of the math is easily handled by a graphing calculator or spreadsheet, so familiarity with the use of those is a great bonus (almost required).

__

You will be better equipped to go into algebra I if you have memorized multiplication tables, rules of divisibility, some mental math procedures, and squares and cubes of small integers (square ≤ 20^2, cubes ≤ 10^3). This will help immensely when it comes to factoring. Similarly, you need to be familiar with arithmetic involving decimals, fractions, and mixed numbers. Numbers in one form should offer you no more challenge than numbers in any other form.

__

A big challenge for many people is the fact that math builds on previous learning. If you don't learn the early stuff well, and practice it a lot, then you will find you have difficulty drawing on that knowledge to make the later stuff easier. It's NOT a "test and forget" sort of deal. It's a "remember this <em>forever</em>" sort of deal.

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Sum of all adjacent angles is 180°.

3x + 12 + x = 180
4x + 12 = 180
4x = 168
x = 42°

-----------------------------------------
Answer: x = 42°
-----------------------------------------
3 0
3 years ago
Please please help me
Gekata [30.6K]

Answer:

\large\boxed{\dfrac{\boxed{8}}{81}}

Step-by-step explanation:

\text{If}\ a_1,\ a_2,\ a_3,\ a_4,\ ...,\ a_n\ \text{is the geometric sequence, then}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...=\dfrac{a_n}{a_{n-1}}=constant=r-\text{common ration}.\\\\\text{We have}\ \dfrac{1}{2},\ \dfrac{1}{3},\ \dfrac{2}{9},\ \dfrac{4}{27},\ ...\\\\\dfrac{\frac{1}{3}}{\frac{1}{2}}=\dfrac{1}{3}\cdot\dfrac{2}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{2}{9}}{\frac{1}{3}}=\dfrac{2}{9}\cdot\dfrac{3}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{4}{27}}{\frac{2}{9}}=\dfrac{4}{27}\cdot\dfrac{9}{2}=\dfrac{2}{3}

\bold{CORRECT}\\\\\dfrac{x}{\frac{4}{27}}=\dfrac{2}{3}\qquad\text{multiply both sides by}\ \dfrac{4}{27}\\\\x=\dfrac{2}{3}\cdot\dfrac{4}{27}\\\\x=\dfrac{8}{81}

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3 years ago
Please help! super urgent!
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Answer:

A. square root of 3 times 5

Step-by-step explanation:

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half of the students in max's class volunteer at a local community center. fifteen students do not volunteer. if there was twelv
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An item that cost $5.50 is marked up %60. What is the new price of the item after the markup? Show work please​
r-ruslan [8.4K]

Answer:

$8.80

Step-by-step explanation:

In order to find the new price, you need to add 60% of the original price (5.50) to the original price. You have two options:

1) multiply $5.50*0.6 to get 60% of the original price. You would get $3.30. Then add $3.30+$5.50, which equals $8.80. This way takes longer but shows you all the steps.

2) The shorter way is to simply multiply $5.50*1.6, which also equals $8.80. This works because the "1" automatically adds the 5.50 to 60% of the original price, this way you don't have to multiply then add.

If you don't understand how the second way works or your teacher taught you #1, just do it the first way.

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