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Pavlova-9 [17]
4 years ago
15

A car has a velocity of 15 m/s.

Physics
1 answer:
yan [13]4 years ago
5 0

Explanation:

Given:

v₀ = 15 m/s

a = 3.5 m/s²

t = 5.0 s

Find: v

v = at + v₀

v = (3.5 m/s²) (5.0 s) + 15 m/s

v = 32.5 m/s

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3 years ago
Read 2 more answers
Two charges 5 c and 15 c are seperated by 10 cm. what is the electric force between them?
icang [17]

Answer:

6.75×10^13N

Explanation:

The electric force between the charges can be determined using coulombs law which states that 'the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of their distance between them.

Mathematically, F = kq1q2/r² where;

q1 and q2 are the charges

r is the distance between the charges

F is the force of attraction

k is the coulombs constant

Given q1 = 5C q2 = 15C r = 10cm = 0.1m k = 9×10^9Nm²/C²

Substituting the given values in the formula we have;

F =9×10^9×5×15/0.1²

F = 6.75×10^11/0.01

F = 6.75×10^13N

Therefore the electric force between them is 6.75×10^13N

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3 years ago
How do sex cells differ from other human cells?
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3/122 The collar has a mass of 2 kg and is attached to the light spring, which has a stiffness of 30 N/m and an unstretched leng
gavmur [86]

Explanation:

According to the law of conservation of energy, work done by the force is as follows.

        W_{F} = F Cos (30^{o}) \times 1.5

                   = 64.95 J

Now, gain in potential energy is as follows.

                P.E = mgh

                      = 2 \times 9.8 \times 1.5

                      = 29.4 J

Gain in potential energy will be as follows.

           = \frac{1}{2}kx^{2}_{2} - \frac{1}{2}kx^{2}_{1}

           = \frac{1}{2} \times 30 N/m \times [(2.5 - 1.5)^{2} - (2 - 1.5)^{2}]

           = 11.25

As,

          W_{f} = u_{1} + u_{2} + \frac{1}{2}mv^{2}

          \frac{1}{2}mv^{2} = W_{f} - u_{1} - u_{2}  

                   = 64.95 J - 29.4 - 11.25

                   = 24.3

              v^{2} = \frac{24.3 \times 2}{2}

                  v = 4.92 m/s

Therefore, we can conclude that relative velocity at point B is 4.92 m/s.  

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20% of injury crashes in 2009 involve the reports of distracted driving. True or false
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The statement is true.

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