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agasfer [191]
3 years ago
9

The engine oil at 150 degree Celsius is cooled to 80 degree Celsius in a parallel flow heat exchanger by water entering at 25 de

gree Celsius and leaving at 60 degree Celsius. Estimate the number of transfer units If you think you require the specific heats for water and oil, use 4.18 and 2.20 respectively

Physics
1 answer:
Setler [38]3 years ago
6 0

Answer:

Explanation:

Attach is the solution

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According to the evolutionary perspective of mate selection, why do men and women exhibit different preferences in mate selectio
Alla [95]

C. Each gender has differing attraction cues and priorities.

<h3>Why do men and women exhibit different preferences in mate selection?</h3>

Men and women exhibit different preferences in mate selection because both have different attraction cues and priorities for their partner. These cues and priorities leads to difference in preference of life partner.

So we can conclude that Each gender has differing attraction cues and priorities.

Learn more about mate here: brainly.com/question/25261401

#SPJ1

6 0
2 years ago
A line of charge starts at x = +x0 and extends to positive infinity. The linear charge density is λ = λ0x0/x. Determine the elec
kari74 [83]

Explanation:

it is given that, the linear charge density of a charge, \lambda=\dfrac{\lambda_ox_o}{x}

Firstly, we can define the electric field for a small element and then integrate for the whole. The very small electric field is given by :

dE=\dfrac{k\ dq}{x^2}..........(1)

The linear charge density is given by :

\lambda=\dfrac{dq}{dx}

dq=\lambda.dx=\dfrac{\lambda_ox_o}{x}dx

Integrating equation (1) from x = x₀ to x = infinity

E=\int\limits^\infty_{x_o} {\dfrac{k\lambda_ox_o}{x^3}}.dx

E=-\dfrac{k\lambda_ox_o}{2}\dfrac{1}{x^2}|_{x_o}^\infty}

E=\dfrac{k\lambda_o}{2x_o}

Hence, this is the required solution.

5 0
3 years ago
Read 2 more answers
If the Sun suddenly went dark, we would not know it until its light stopped arriving on Earth. How long would that be, in second
Gre4nikov [31]

Answer: 500 s

Explanation:

Speed v is defined as a relation between the distance d and time t:

v=\frac{d}{t}

Where:

v=3(10)^{8}m/s is the speed of light in vacuum

d=1.5(10)^{11}m is the distance between the Earth and Sun

t is the time it takes to the light to travel the distance d

Isolating t:

t=\frac{d}{v}

t=\frac{1.5(10)^{11}m}{3(10)^{8}m/s}

Finally:

t=500 s

5 0
3 years ago
The distance between earth and sun is 15000000km. Light takes 499 seconds to reach earth from sun. Calculate the speed of light
iVinArrow [24]

To solve the problem we must know about the relationship between Speed, distance, and Time.

<h3>What is the relationship between Speed, distance, and Time?</h3>

We know that sped, distance, and time all are in a relationship to each other. this relationship can be given as,

\rm{Speed = \dfrac{Distance}{Time}

The speed of the light is 30,060.12 km/sec.

Given to us

  • The distance between the earth and the sun is 15000000km
  • Light takes 499 seconds to reach earth from the sun.

We know that speed can be described as,

\rm{Speed = \dfrac{Distance}{Time}

Therefore,

<h3>What is the speed of the light?</h3>

\text{Speed of light} = \dfrac{\text{Distance between the earth and the sun}}{\text{Time taken by the light to travel the distance}}

Substitute the value,

\text{Speed of light} = \dfrac{15,000,000\ km}{499\ seconds}

\text{Speed of light} = 30,060.12\ km/sec

Hence, the speed of the light is  30,060.12 km/sec.

Learn more about Speed, distance, and Time:

brainly.com/question/15100898

7 0
3 years ago
Read 2 more answers
Bus starts from rest if the acceleration of the bus is 0.5 MS squared what will be the velocity at the end of two minutes and wh
Nutka1998 [239]

Explanation:

Given that,

Initial speed of the bus, u = 0

Acceleration of the bus, a = 0.5 m/s²

Let v is the velocity at the end of 2 minutes. The change in velocity divided by time equals acceleration.

So,

a=\dfrac{v-u}{t}\\\\v=u+at\\\\v=0+0.5\times 120\\\\v=60\ m/s

Let d is the distance cover during that time. So,

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(60)^2}{2\times 0.5}\\\\d=3600\ m

So, the final speed is 60 m/s and the distance covered during that time is 3600 m.

4 0
3 years ago
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