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HACTEHA [7]
3 years ago
6

Write the annual salary in the blanks in the following chart.

Mathematics
2 answers:
bearhunter [10]3 years ago
4 0

1300 monthly= 15600 annually

1000 biweekly= 24000 annually

550 weekly= 26400 annually

800 semimonthly= 19200 annually

btw annually means yearly

Setler79 [48]3 years ago
4 0

15600

24000

26400

19200

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Ok so i have to do this assginemnt and i didn't know it existed so plz answer this question-
Galina-37 [17]

Answer:

$600 (ML),  $200 (MW), $1,035 (total raised), $965 (need to raise needed)

Step-by-step explanation:

50 %   50/100 = 0.5

$1200 x 0.5 = $600 Mrs LeBlanc's class has raised

$600/3 = $200 Ms. Warner's class has raised (MW)

600 + 200 + 235.14 = $ 1,035 Has been raised

1,200 - 1,035 =  $965  is the amount they still need to raise

5 0
3 years ago
Find the perimeter of the trapezoid <br> (5,1)( 5,-4) (1,1) (-2,-4)
klemol [59]

Answer:

i cold not find the answer

Step-by-step explanation:

6 0
3 years ago
An automobile manufacturer claims that its car has a 42.8 miles/gallon (MPG) rating. An independent testing firm has been contra
yanalaym [24]

Answer: -1.51

Step-by-step explanation:

Let \mu be the population mean rating of car.

As per given , we have

H_0: \mu=42.8

H_a: \mu\neq42.8

Since population variance is known, so we use z-test.

Test statistic : z=\dfrac{\overline{x}-\mu}{\sqrt{\dfrac{\sigma^2}{n}}}

, where n= sample size

\overline{x} = Sample mean

\sigma^2= variance

As per given ,

n=300

\overline{x}=42.6

\sigma^2=5.29

\mu=42.8

Put these values in formula we get

z=\dfrac{42.6-42.8}{\sqrt{\dfrac{5.29}{300}}}

z=\dfrac{-0.2}{\sqrt{0.0176333}}

z=\dfrac{-0.2}{0.13279}=-1.50613751035\approx1.51

Hence, the value of the test statistic is z= -1.51 .

3 0
4 years ago
Which of the following equations are written in standard form?
alisha [4.7K]
Answer b looks correct to me
6 0
3 years ago
Read 2 more answers
(8+k³-6k⁴)+(4-3k⁴+8k²)​
ANEK [815]

Answer:

12 + 8k² + k³ - 9k⁴

Step-by-step explanation:

(8 + k³ - 6k⁴) + (4 - 3k⁴ + 8k²)

8 + k³ - 6k⁴ + 4 - 3k⁴ + 8k²

(8 + 4) + (8k²) + (k³) + (-6k⁴ -3k⁴)

(12) + (8k²) + (k³) + (-9k⁴)

12 + 8k² + k³ - 9k⁴

6 0
3 years ago
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