44,800 because in 44,816 the 1 is in the hundreds place and since it's smaller than one its going to be a 0
Answer:
No, the reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Step-by-step explanation:
Consider the provided information.
We need to determine that the reference point selected for the properties of a substance have any effect on thermodynamic analysis.
The answer for this question is No.
The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Because in thermodynamic analysis we are deal with the change in the properties.
If we are doing calculation, the reference state chosen is irrelevant as long as we use values in a single consistent array of tables and charts.
Hence, The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
He pays $780 for the television set.
1200*.35=420
1200-420=780
Answer:
1/40
219/250
69/16
Step-by-step explanation:
1.
0.025=(025)/(1000)=1/40
2.
0.876=876/1000=219/250
3.
4.3125=43125/10000=1725/400=69/16
Part B is not clear and the clear one is;
P(X ≥ 6)
Answer:
A) 0.238
B) 0.478
C) 0.114
Step-by-step explanation:
To solve this, we will make use of binomial probability formula;
P(X = x) = nCx × p^(x)•(1 - p) ^(n - x)
A) 54% of U.S. adults have very little confidence in newspapers. Thus;
p = 0.54
10 random adults are selected. Thus;
P(X = 5) = 10C5 × 0.54^(5) × (1 - 0.54)^(10 - 5)
P(X = 5) = 0.238
B) P(X ≥ 6) = P(6) + P(7) + P(8) + P(9) + P(10)
From online binomial probability calculator, we have;
P(X ≥ 6) = 0.2331 + 0.1564 + 0.0688 + 0.01796 + 0.0021 = 0.47836 ≈ 0.478
C) P(x<4) = P(3) + P(2) + P(1) + P(0)
Again with online binomial probability calculations, we have;
P(x<4) = 0.1141 ≈ 0.114
