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ale4655 [162]
3 years ago
7

I need help finding the answers. Idk how to do it. If I did then I could find it. Help plz

Mathematics
1 answer:
mestny [16]3 years ago
8 0

Answer:

THAT SOME HARD MATHHH

Step-by-step explanation:

BECAUSE ITS HARD

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1/2÷5= to a improper fraction
Leokris [45]
1/10
hope this helps u out!
5 0
3 years ago
The circumference of a circle is 65?. In terms of pi, what is the area of the circle?
iVinArrow [24]

Answer:

1056.25π square units

Step-by-step explanation:

A few formulas an definitions which will help us:

(1) \pi=\frac{c}{d}, where c is the circumference of a circle and d is its diameter

(2) A=\pi r^2, where A is the area of a circle with radius r. To put it in terms of d, remember that a circle's diameter is simply twice its radius, or mathematically, (3) d=2r \rightarrow r=\frac{d}{2}.

We can rearrange equation (1) to put d in terms of π and c, giving us (4) d = \frac{c}{\pi}, and we can make a few substitutions in (2) using (3) and (4) to get use the area in terms of the circumference and π:

A=\pi r^2\\=\pi\left(\frac{d}{2}\right)^2\\=\pi\left(\frac{d^2}{4}\right)\\=\pi\left(\frac{(c/\pi)^2}{4}\right)\\=\pi\left(\frac{c^2/\pi^2}{4}\right)\\=\pi\left(\frac{c^2}{4\pi^2}\right)\\\\=\frac{\pi c^2}{4\pi^2}\\ =\frac{c^2}{4\pi}

We can now substitute c for our circumference, 65, to get our answer in terms of π:

A=\dfrac{65^2}{4\pi}=\dfrac{4225}{4\pi}=1056.25\pi

8 0
3 years ago
Read 2 more answers
What are the roots of the graph below?
Nostrana [21]

Answer:

-2,-1,1,2

Step-by-step explanation:

The term root is just another name for the x intercept so just look at where your line crosses the x axis and you will have your answer. Remember the y axis is not involved so it cannot be a co-ordinate.

4 0
3 years ago
What percent of 25 is 5
SSSSS [86.1K]
What percent of 25 is 5?

5/25

5 ÷ 25 = 0.2 

0.2 × 100 = 20
20%

5 is 20% of 20. 
6 0
3 years ago
Read 2 more answers
What is the solution to -x2 + 5x - 3
CaHeK987 [17]

The solution to the equation is x=\frac{5-\sqrt{13}}{2} and x=\frac{5+\sqrt{13}}{2}

Explanation:

Given that the equation is -x^2+5x-3=0

We need to determine the solution of the equation.

The solution of the equation can be determined using the quadratic formula.

The quadratic formula is given by

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Hence, from the equation, we have,

a=-1,\:b=5,\:c=-3

Substituting these values in the quadratic formula, we get,

x=\frac{-5\pm \sqrt{5^2-4\left(-1\right)\left(-3\right)}}{2\left(-1\right)}

Simplifying, we get,

x=\frac{-5\pm \sqrt{25-12}}{-2}

Simplifying the terms within the root, we get,

x=\frac{-5\pm \sqrt{13}}{-2}

Thus, the roots of the equation are x=\frac{-5+ \sqrt{13}}{-2} and x=\frac{-5- \sqrt{13}}{-2}

Taking out the negative sign, we get,

x=\frac{-(5- \sqrt{13})}{-2} and x=\frac{-(5+ \sqrt{13})}{-2}

Cancelling the negative sign, we get,

x=\frac{5-\sqrt{13}}{2} and x=\frac{5+\sqrt{13}}{2}

Thus, the solutions of the equation are x=\frac{5-\sqrt{13}}{2} and x=\frac{5+\sqrt{13}}{2}

7 0
3 years ago
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