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ale4655 [162]
4 years ago
7

I need help finding the answers. Idk how to do it. If I did then I could find it. Help plz

Mathematics
1 answer:
mestny [16]4 years ago
8 0

Answer:

THAT SOME HARD MATHHH

Step-by-step explanation:

BECAUSE ITS HARD

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Write an<br> explicit formula for<br> then<br> th<br> an.<br> term of the sequence 45, 15,5. ....
7nadin3 [17]

Answer:

The sequence above is a geometric sequence

For an nth in a geometric sequence

u(n) = a {r}^{n - 1}

where n is the number of terms

a is the first term

r is the common ratio

From the question

a = 45

r = 15 / 45

The explicit formula for the sequence is

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Hope this helps you

7 0
3 years ago
Two gears are adjusted so that the smaller gear drives the larger one. if the smaller gear of 3.7cm rotates through an angle of
zepelin [54]

Answer:

<em>The larger gear will rotate through 156°</em>

Step-by-step explanation:

<u>Arc Length</u>

The arc length S of an angle θ on a circle of radius r is:

S = \theta r

Where θ is expressed in radians.

The smaller gear of r1=3.7 cm drives a larger gear of r2=7.1 cm. The smaller gear rotates through an angle of θ1=300°.

Convert the angle to radians:

\displaystyle \theta_1=300*\frac{\pi}{180}=\frac{5\pi}{3}

The arc length of the smaller gear is:

\displaystyle S_1=\frac{5\pi}{3}\cdot 3.7

\displaystyle S_1=\frac{18.5\pi}{3}

The larger gear rotates the same arc length, so:

\displaystyle S_2=\frac{18.5\pi}{3}

\displaystyle \theta_2\cdot r_2=\frac{18.5\pi}{3}

Solving for θ2:

\displaystyle \theta_2=\frac{18.5\pi}{3r_2}

\displaystyle \theta_2=\frac{18.5\pi}{3*7.1}

\theta_2=2.73\ radians

\displaystyle \theta_2=2.73*\frac{180}{\pi}=156

The larger gear will rotate through 156°

7 0
3 years ago
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ira [324]
I show working but this is the answer <span>m=<span>1/2</span></span>
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3 years ago
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Step-by-step explanation:

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3 years ago
Perform the operation and, if possible, simplify<br> 21/20 - 4/15
Kazeer [188]

Answer:

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Step-by-step explanation:

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