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Alex_Xolod [135]
3 years ago
12

THE VALUE OF (-3)raised to 4 is

Mathematics
1 answer:
Finger [1]3 years ago
7 0

Step-by-step explanation:

81

I think this should be the answer

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Find the length of the
mr_godi [17]

Answer:

I think you write a wrong question

write this question again

6 0
3 years ago
5x+4 HELP ME PLS it’s for a test I have right now
saveliy_v [14]

Answer:

Here is a graph of that equation.

Let me know if you need more help! :)

4 0
3 years ago
Read 2 more answers
Simplify <br> 7.2x10^3/1.8x10^7
spayn [35]

To simplify and solve this equation we must follow PEMDAS.

P=Parentheses

E=Exponents

M=Multiplication (from left to right)

D=Division (from left to right)

A=Addition

S=Substraction

We begin the process.

10^3=1000

10^7=10000000

New equation looks like this:

7.2*1000/1.8*10000000

We then multiply

7.2*1000= 7200

7200/1.8=4000

4000*10000000= 40000000000

<em>So our final answer is 40000000000.</em>

Hope this helps!

P.S. I forgot this was scientific notation and I solved it a different way. But both ways give the same answer. Let me know if you want the other method.


3 0
3 years ago
state the domain, the range, and the intervals on which function is increasing, decreasing, or constant in interval notation
erma4kov [3.2K]

Answer:

  • domain (-∞, ∞)
  • range (-∞, 4]
  • increasing (-∞, 0)
  • decreasing (0, ∞)
  • constant (only at x=0, not on any interval)

Step-by-step explanation:

The graph is of the equation y = -x^2 +4. It is a polynomial of even degree, so has a domain of all real numbers: (-∞, ∞).

The vertical extent of the graph includes y=4 and all numbers less than that:

  range: (-∞, 4]

The graph is increasing to the left of its vertex at x=0, decreasing to the right.

  increasing (-∞, 0); decreasing (0, ∞)

There is no interval on which the function is constant. It has a horizontal tangent at x=0, but a single point does not constitute an interval.

8 0
3 years ago
Multiples comunes de 6 y 9
Sindrei [870]
Multiples communes de 6 y 9 son 18 y 36
6 0
3 years ago
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