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loris [4]
3 years ago
10

What expression is equivalent to (1/16)^-4

Mathematics
2 answers:
otez555 [7]3 years ago
7 0

16^4  Hope this helps.

Marizza181 [45]3 years ago
7 0

Answer:

16 ⁴

Step-by-step explanation:

use a -n= (1/a)n

(1/16 - ⁴= ( 16/ 1 )

=16 ⁴

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The answer is B .greater than 6
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-4x-10=2x+14<br><br> solve for x
natta225 [31]
I did the math I think it’s 12
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Find the difference. express the answer in scientific notation. (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 sup
Georgia [21]

The difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

<h3>How to determine the notation</h3>

Given the expression

(5. 29 × 10^11) - (3. 86 × 10 ^11)

First, find the common factor

10^11 ( 5. 29 - 3. 86)

Then substract the values within the bracket

10^11 (1. 43)

Multiply with the factor, we have

⇒1. 43 × 10^11

Thus, the difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

Learn more about index notation here:

brainly.com/question/10339517

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7 0
2 years ago
Mrs. Bailey gives a test, and her students’ scores range from 30 to 70. She decides to curve the scores, so that they range from
Harman [31]

Answer:

f(x) = x*3/4 + 42.5

Step-by-step explanation:

The original difference between the pair is 70 - 30 = 40

The new difference between the pair is 95 - 65 = 30

Since the differences are not the same, Mrs Bailey must first perform a (slope) multiplication by a factor of 30/40 or 3/4

Then 30 * 3/4 = 22.5

Then she can shift the scores up by 65 - 22.5 = 42.5 in order to get the range from 65 to 95

Therefore, f(x) = x*3/4 + 42.5. We can test that

f(30) = 30*3/4 + 42.5 = 65

f(70) = 70*3/4 + 42.5 = 95

8 0
3 years ago
Enter an equation for the function that includes the points.Give your answer in a(b)x. In the event that a=1 , give your answer
Andrews [41]

Answer:

f(x) = \frac{24}{25} * \frac{5}{6}^x

Step-by-step explanation:

Given

(x_1,y_1) = (2,\frac{2}{3})

(x_2,y_2) = (3,\frac{5}{9})

Required

Write the equation of the function f(x) = ab^x

Express the function as:

y = ab^x

In: (x_1,y_1) = (2,\frac{2}{3})

y = ab^x

\frac{2}{3} = a * b^2 --- (1)

In (x_2,y_2) = (3,\frac{5}{9})

y = ab^x

\frac{5}{9} = a * b^3 --- (2)

Divide (2) by (1)

\frac{5}{9}/\frac{2}{3} = \frac{a*b^3}{a*b^2}

\frac{5}{9}/\frac{2}{3} = b

\frac{5}{9}*\frac{3}{2} = b

\frac{5}{3}*\frac{1}{2} = b

\frac{5}{6} = b

b = \frac{5}{6}

Substitute 5/6 for b in (1)

\frac{2}{3} = a * b^2

\frac{2}{3} = a * \frac{5}{6}^2

\frac{2}{3} = a * \frac{25}{36}

a = \frac{2}{3} * \frac{36}{25}

a = \frac{2}{1} * \frac{12}{25}

a = \frac{24}{25}

The function: f(x) = ab^x

f(x) = \frac{24}{25} * \frac{5}{6}^x

7 0
3 years ago
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