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tester [92]
3 years ago
6

Craig works at a restaurant for 21 hours in January. at this rate, how many hours will he work after 7.5 months?

Mathematics
2 answers:
My name is Ann [436]3 years ago
8 0

Answer:

around 4725

Step-by-step explanation:

algol [13]3 years ago
8 0

Answer:

157.5 hours

Step-by-step explanation:

If Craig continued to work 21 hours for 7.5 months he would work a total of 157.5 hours.

Why?

Because if you multiply 21 seven times you get a total of 147 hours, but we still have the .5 of the month so take 21 and divide it by 2 which gives us 10.5 hours.

When you have both you outcomes ready you add 147 and 10.5 hours

Which gives us 147+10.5=157.5 hours.

Good luck :)

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Sophia owns a clothing store that sells graphic T-shirts. n is the number of
goldenfox [79]

Answer:

n = 150

Step-by-step explanation:

If n is the number of T-shirt sell each month, then the revenue function of Sophia's store is r = 21n .......... (1)

and the cost function of her store is C = 16n + 750 ........ (2)

Now, at break-even point, the revenue of a business is equal to its cost.

Therefore, r = C {From equations (1) and (2)}

⇒ 21n = 16n + 750

⇒ 5n = 750

⇒ n = 150

So, the break-even point of the store will occur when the number of T-shirt production is 150. (Answer)

8 0
3 years ago
Which is one reason why this expression is equal to 0?
Shtirlitz [24]
If there is no expression, it surely is equal to 0.
5 0
4 years ago
Read 2 more answers
Find the missing values in the following figures​
jekas [21]

Answer:

15.

  x = 40/9 = 4 4/9

  z = 24/5 = 4 4/5

17.

  x = 50

  y ≈ 11.5

Step-by-step explanation:

15. Corresponding segments are proportional:

  top right side / whole right side = x / 8

  5/(5+4) = x/8

  x = 8(5/9) = 40/9

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__

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____

17. The acute angles are complementary:

  x = 90 -40 = 50

__

From the Pythagorean theorem:

  y = √(15² -9.6²) = √132.84

  y ≈ 11.5

4 0
3 years ago
When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither nu
o-na [289]
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x + y = 3 and <span>2x + 2y = 6
Determinant of the equations are </span>
<span>| 1 1 | </span>
<span>| 2 2 | = 0
</span>
the numerator determinants would be
<span>| 3 1 | . .| 1 3 | </span>
<span>| 6 2 | = | 2 6 | = 0.
Executing Gauss Elimination, any two numbers, whose sum is 3, would satisfy the given system. F</span>or instance (3, 0), <span>(2, 1) and (4, -1). Therefore, it would have infinitely many solutions. </span>
3 0
3 years ago
Daniel reads dor 8 times as many as April. Daniel read 44 minutes this week. How many minutes does April read?
ELEN [110]
44 [minutes] * 8 [times as many as April] = 352 [minutes in April]
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