Answer:
c
Step-by-step explanation:
Two sum of any two side lengths of a triangle will always be greater than the length of the remaining side
a doesn't work because 8+12=20 and 20 is not greater than 20
b doesn't work because 4+5=9 and 9<10
d doesn't work because 6+6=12 and 12 is not greater than 12
c is the only option where you can take any two sides, add them, and the sum will be greater than the remaining side.
For example, for c,
6+8=14, and 14>10
8+10=18, and 18>6
10+6=16, and 16>8
The answer is 3x-3. You have to distribute the 3 to both of the variables in the equations. The 1 in the parentheses is a negative and multiplying the 3 will result in a negative 3.
Answer:
Well ,lets see∉ if you add theose numbers togetherФ it maybe it he answer is 4=67 *64 ---4 67x54 5xe4t4 6x
I have to interpret that:
1) the smaller square has side length = 3 cm
2) the bigger square has side length = 5 cm
3) the smaller square is completely inside the bigger square.
4) the points cannot be outside the bigger square
Under those assumptions the probability that a point is inside the smaller square is
P (inside the smaller square) = area of the smaller square / area of the bigger square
P (inside the smaller squere) = (3cm)^2 / (5cm)^2 = 9 / 25
Answer: 9 / 25
Answer:
-4/8
Step-by-step explanation:
that's what my math says
