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3 years ago

Plzzzz Help meeeeee!!!!!!

Mathematics

1 answer:

mariarad [96]3 years ago

5 0

Answer:

The cost of the $0.5 per cookies and $1.25 per brownie.

Option (A) is correct.

Step-by-step explanation:

Let us assume that the cost of the cookies =x

Let us assume that the cost of the brownie = y

As given

Sara is selling cookies and brownies as a fundraiser for the school band.

She charges $2.25 for two cookies and one brownie.

Than the equation becomes

2x + y = 2.25

She charges $5.75 for four cookies and three brownies.

4x + 3y = 5.75

Than two equation are

2x + y = 2.25 and 4x + 3y = 5.75

Multiply 2x + y = 2.25 by 3 and subtracted from 4x + 3y = 5.75

4x - 6x + 3y - 3y = 5.75 - 6.75

-2x = - 1

2x = 1

$x = \frac{1}{2}$

x = $0.5

Put in the equation 2x + y = 2.25

2 × 0.5 + y = 2.25

1 + y = 2.25

y = 2.25 - 1

y = $1.25

Therefore the cost of the $0.5 per cookies and $1.25 per brownie.

Option (A) is correct.

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Select all expressions that represent a correct solution to the equation 6(x+4)=20. copied for free from openupresources.Org Sel

baherus [9]

Option D: $20 \div 6-4$ is the correct solution to the equation $6(x+4)=20$

Option E: $\frac{1}{6} (20-24)$ is the correct solution to the equation $6(x+4)=20$

Option F: $(20-24) \div 6$ is the correct solution to the equation $6(x+4)=20$

Explanation:

The expression is $6(x+4)=20$

Let us find the value of x.

$\begin{aligned}6(x+4) &=20 \\6 x+24 &=20 \\6 x &=-4 \\x &=-\frac{2}{3}\end{aligned}$

Now, we shall find the expression that is equivalent to the value $x=-\frac{2}{3}$

Option A: $(20-4) \div 6$

Simplifying the expression, we have,

$\frac{16}{6}=\frac{8}{3}$

Since, $\frac{8}{3}$ is not equivalent to $x=-\frac{2}{3}$ , the expression $(20-4) \div 6$ is not equivalent to the equation $6(x+4)=20$

Hence, Option A is not the correct answer.

Option B: $16(20-4)$

Simplifying the expression, we have,

$16(16)=256$

Since, 256 is not equivalent to $x=-\frac{2}{3}$ , the expression $16(20-4)$ is not equivalent to the equation $6(x+4)=20$

Hence, Option B is not the correct answer.

Option C: $20-6-4$

Simplifying the expression, we have,

$20-10=10$

Since, 10 is not equivalent to $x=-\frac{2}{3}$ , the expression $20-6-4$ is not equivalent to the equation $6(x+4)=20$

Hence, Option C is not the correct answer.

Option D: $20 \div 6-4$

Using PEMDAS and simplifying the expression, we have,

$\begin{aligned}(20 \div 6)-4 &=\frac{10}{3}-4 \\ &=\frac{10-12}{3} \\ &=-\frac{2}{3} \end{aligned}$

Thus, $-\frac{2}{3}$ is equivalent to $x=-\frac{2}{3}$ , the expression $20 \div 6-4$ is equivalent to the equation $6(x+4)=20$

Hence, Option D is the correct answer.

Option E: $\frac{1}{6} (20-24)$

Simplifying the expression, we have,

$\begin{aligned} \frac{1}{6}(20-24) &=\frac{1}{6}(-4) \\ &=-\frac{4}{6} \\ &=-\frac{2}{3} \end{aligned}$

Thus, $-\frac{2}{3}$ is equivalent to $x=-\frac{2}{3}$ , the expression $\frac{1}{6} (20-24)$ is equivalent to the equation $6(x+4)=20$

Hence, Option E is the correct answer.

Option F: $(20-24) \div 6$

Simplifying the expression, we have,

$\begin{aligned}(20-24) \div 6 &=-\frac{4}{6} \\ &=-\frac{2}{3} \end{aligned}$

Thus, $-\frac{2}{3}$ is equivalent to $x=-\frac{2}{3}$ , the expression $(20-24) \div 6$ is equivalent to the equation $6(x+4)=20$

Hence, Option F is the correct answer.

6 0

4 years ago

If I have 48 cards and and gave 10 to my friend and I have 38 left what what fractionbb be is my original number of cards

topjm [15]

Question isn't well formatted :

If I have 48 cards and and gave 10 to my friend and I have 38 left. what fraction of original number of card do I have left.

Answer:

0.7917

Step-by-step explanation:

If I have 48 cards and and gave 10 to my friend and I have 38 left what what fractionbb be is my original number of cards

Given that :

Total number of cards = 48

Number given to friend = 10

Number of cards left = 48 - 10 = 38

Number of cards left / original number of cards

38 / 48

= 0.7917

8 0

3 years ago

"15. describe the three data fragmentation strategies. give some examples of each."

OlgaM077 [116]

1. Horizontal fragmentation – a table is separated into groups of rows rationally and each fragment (group/sunset) comprises unique rows and it is kept at different node. All rows have the same attributes and the SELECT statement yields the contents of the fragments.
2. Vertical fragmentation – the table is distributed into rational groups of attributes (columns). Each fragment covers a unique columns and is stored at a dissimilar position. The content in the fragment is attained by using the “PROJECT” statement.
3. Mixed fragmentation –This approach is the mix of horizontal and vertical strategies. In other words, each row fragment may be a blend of groups of attributes.

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4 years ago

Which is one of the transformations applied to the graph of f(x) = x2 to change it into the graph of g(x) = 4x2 + 24x + 30?

WARRIOR [948]

Changing g(x) to this form: a(x-h) + k, we have:
g(x) = 4 (x+3)^2 - 6

Comparing this to the original equation, f(x) = x^2, we have the following transformations:

The graph is widened.
The graph is shifted left 3 units.

6 0

4 years ago

Bashir was out at a restaurant for dinner when the bill came. His dinner came to $32.

Vladimir [108]

Answer:

23%

Step-by-step explanation:

39.36-32=7.36

7.36/32=.23

23 percent

4 0

2 years ago