13.23 is the answer for that equation
Answer:
2 unit/time²
Step-by-step explanation:
Given the equation:
v(t) =t^2-3t
At interval ; 1, 4
V(1) = 1^2 - 3(1)
V(1) = 1 - 3
V(1) = - 2
At t = 4
V(4) = 4^2 - 3(4)
V(4) = 16 - 12
V(4) = 4
Average acceleration : (final - Initial Velocity) / change in time
Average acceleration = (4 - (-2)) ÷ (4 - 1)
Average acceleration = (4 + 2) / 3
Average acceleration = 6 /3
Average acceleration = 2
1 clipe..............7/8
x.......................56
7x/8 = 56
7x = 56*8
x = 56*8/7
x = 8*8
x = 64 clipes
1 clipe = 0,03
64 clipes = 0,03*64
64 clipes = 1,92
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