Answer:

Step-by-step explanation:
The properties of circumcenter give that it lies at the midpoint of the hypotenuse if it is of a right triangle.
Now, the given triangle is a right triangle and the two ends of the hypotenuse WU are U(-3,2) and W(4,-3).
Therefore, the mid point of the hypotenuse WU will be given by
.
Therefore, the circumcenter of the right triangle Δ UVW will be
. (Answer)
Okay, you will need to use the law of cosines for this problem.
The Law of Cosines states (in this case): a^2 = b^2 + c^2 - 2 * b * c * cos A, where "a" is the side opposite angle A (7 inches), and b and c are the other two sides.
Plug the numbers in and you get: 7^2 = 5^2 + 9^2 - 2 * 5 * 9 * cos A, or:
49 = 25 + 81 - 90 * cos A.
Subtract (25 + 81) from both sides to get:
-57 = -90 * cos A.
Divide by -90 on both sides:
cos A = 19/30
To find A, you do the inverse trigonometric function to get:
cos^-1 of (19/30) = A.
I don't have a calculator that can do this right now, but if you plug the left side of the above equation into it (make sure it is in degrees, not radians), you should get A.
Answer:
He would need 3/4 a gallon to paint the wall
Step-by-step explanation:
Answer:
(8,150)
Step-by-step explanation:
Polar form is in,
(r,theta).
To find r, apply pythagorean theorem using both coordinates to find r.



To find theta, since we know the opposite and adjacent side, apply the tangent function.

Apply inverse tan function

Since the degrees have to be in between 0 and 360. Add 180 to -30.

So the answer is
(8,150).
Answer:
The time of a commercial airplane is 280 minutes
Step-by-step explanation:
Let
x -----> the speed of a commercial airplane
y ----> the speed of a jet plane
t -----> the time that a jet airplane takes from Vancouver to Regina
we know that
The speed is equal to divide the distance by the time
y=2x ----> equation A
<u><em>The speed of a commercial airplane is equal to</em></u>
x=1,730/(t+140) ----> equation B
<u><em>The speed of a jet airplane is equal to</em></u>
y=1,730/t -----> equation C
substitute equation B and equation C in equation A
1,730/t=2(1,730/(t+140))
Solve for t
1/t=(2/(t+140))
t+140=2t
2t-t=140
t=140 minutes
therefore
The time of a commercial airplane is
t+140=140+140=280 minutes