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3 years ago

What is the best approximation for √29? 5 5.2 5.9 6

Mathematics

2 answers:

AleksandrR [38]3 years ago

5 0

Answer:

5.2

Plz mark me as brainliest.

Helen [10]3 years ago

3 0

Answer:

Hello, Brainly users, hi hows your day going. Great. Yeah thanks for asking. Anyway, the answer is 5.2.

Step-by-step explanation:

Will provide step-by-step explanation as to how I figured it out if I can get brainliest *HINT HINT*. Have a good day. And keep good vibes amid the pandemic

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1/2 x + y = 8 and 2y = x + 14<br> pls show your work thx

Fudgin [204]

9514 1404 393

Answer:

(x, y) = (1, 7.5)

Step-by-step explanation:

Solve the first equation for y, then substitute into the second equation.

y = 8 -1/2x . . . . . subtract 1/2x

2(8 -1/2x) = x +14

16 -x = x + 14 . . .eliminate parentheses

2 = 2x . . . . . . . add x-14

1 = x . . . . . . . . divide by 2

y = 8 -1/2(1) = 7 1/2

The solution is (x, y) = (1, 7 1/2).

<em>Alternate solution</em>

Type the equations into a graphing calculator and let it show you the solution.

3 0

3 years ago

1/4(12x+16)=10-3(x-2) anyone?

enyata [817]

$\frac{1}{4}(12x+16)=10-3(x-2)\\\\3x+4=10-3x+6\\\\3x+4=16-3x\ \ \ \ \ \ |subtract\ 4\ from\ both\ sides\\\\3x=12-3x\ \ \ \ \ \ \ |add\ 3x\ to\ both\ sides\\\\6x=12\ \ \ \ \ \ \ |divide\ both\ sides\ by\ 6\\\\\boxed{x=2}$

5 0

4 years ago

Kendrenks kennel has 2 spots for cats for every 7 spots for dogs if he has a total og 144 spots for both cats and dogs then how

ch4aika [34]

Answer:

Kendrenks kennel has 80 more spots for dogs than spots for cats

Step-by-step explanation:

First of all we are going to define the unknowns of the problem, so $x$ number of spots for cats and $y$ number of spots for dogs. Then as the problem has two unknowns, we have to build two equations to solve it.

Using "if he has a total of 144 spots for both cats and dogs" we have one, so

$(1) \ x+y=144$

Then "Kendrenks kennel has 2 spots for cats for every 7 spots for dogs", the other one $(2) \ x=\frac{2y}{7}$ .

Replace (2) in (1) we get $\frac{2y}{7} +y=144$ , multiplying both sides by 7 $2y+7y=1008\\9y=1008\\y=\frac{1008}{9} =112\ Dogs\ Spots$ , then this info in (2) $x=\frac{2y}{7}=\frac{2(112)}{7}=\frac{224}{7}=32\ Cats\ Spots$ .