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2 years ago

What is the best approximation for √29? 5 5.2 5.9 6

Mathematics

2 answers:

AleksandrR [38]2 years ago

5 0

Answer:

5.2

Plz mark me as brainliest.

Helen [10]2 years ago

3 0

Answer:

Hello, Brainly users, hi hows your day going. Great. Yeah thanks for asking. Anyway, the answer is 5.2.

Step-by-step explanation:

Will provide step-by-step explanation as to how I figured it out if I can get brainliest *HINT HINT*. Have a good day. And keep good vibes amid the pandemic

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In Exercises 1–6, write the first five terms of the sequence whose th term is given.

Vadim26 [7]

Answer:

Step-by-step explanation:

1. Un = 3^ n

U1 = 3, U2 = 9, U3 = 27, U4 = 81, U5 = 243

2. Un = (-2/5)^n

U1 = -2/5, U2 = 4/25, U3 = 8/125, U4 = 16/625, U5 = 32/3125

3. Un = sin npi/2

U1 = 1, U2 = 0, U3 = -1, U4 = 0, U5 = -1

4. Un = 3n/n+4

U1 = 3/5, U2 = 1, U3 = 9/7, U4 = 3/2, U5 = 5/3

5. Un = (-1)^n+1(2/n)

U1 = 1, U2 = 2, U3 = -1/3, U4 = 3/2, U5 = -3/5

6. Un = 2 + 2/n - 1/n^2

U1 = 3, U2 = 11/4, U3 = 23/9, U4 = 39/16, U5 = 59/25

7 0

3 years ago

Factor the expression and simplify as much as possible. 24x(x2 1)4(x3 1)5 42x2(x2 1)5(x3 1)4

zmey [24]

Answer: 120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]

Step-by-step explanation:

=24x(x^2 + 1)4(x^3 + 1)5 + 42x^2(x^2 + 1)5(x^3 + 1)4

Remove the brackets first

=[(24x^3 +24x)(4x^3 + 4)]5 + [(42x^4 +42x^2)(5x^3 + 5)4]

=[(96x^6 + 96x^3 +96x^4 + 96x)5] + [(210x^7 + 210x^4 + 210x^5 + 210x^2)4]

=(480x^6 + 480x^3 + 480x^4 + 480x) + (840x^7 + 840x^4 + 840x^5 + 840x^2)

Then the common:

=[480(x^6 + x^3 + x^4 + x) + 840(x^7 + x^4 + x^5 + x^2)]

=120[4(x^6 + x^3 + x^4 + x) +7(x^7 + x^4 + x^5 + x^2)]

6 0

3 years ago

Solve for A if F=MA and F=10 and M=2.5

gogolik [260]

Answer:

$\boxed{\sf A = 4}$

Given:

F = MA

F = 10

M = 2.5

To Find:

Value of A

Step-by-step explanation:

$\sf Substituting \ values \ of \ F \ and \ M \ in \ F = MA:$

$\sf \implies 10 = 2.5A$

$\sf \implies 2.5A = 10$

$\sf Dividing \ both \ side \ of \ 2.5A = 10 \ by \ 2.5:$

$\sf \implies \frac{2.5}{2.5} A = \frac{10}{2.5}$

$\sf \frac{2.5}{2.5} = 1 :$

$\sf \implies A = \frac{10}{2.5}$

$\sf \frac{4 \times \cancel{2.5}}{ \cancel{2.5}} = 4 :$

$\sf \implies A = 4$

3 0

3 years ago

Read 2 more answers

Hey can you please help me posted picture of question

Debora [2.8K]

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = -11
a = coefficient of squared term = 2
c = constant term = 15

Using the values, we get:
$x= \frac{11+- \sqrt{121-4(2)(15)} }{2(2)} \\ \\ 
x= \frac{11+-1}{4} \\ \\ 
x=3, x= 2.5$

So, the correct answer to this question are option B and D

4 0

3 years ago

BRAINLIEST if correct 4

Viefleur [7K]

Answer:

Yes it is biased

Step-by-step explanation:

It shows favoritism

4 0

3 years ago

Read 2 more answers