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Zarrin [17]
3 years ago
15

Eq-41 if pyrotechnic visual distress signals are required, how many must be onboard?

Mathematics
1 answer:
Lorico [155]3 years ago
7 0
The answer is 3 (mostly must be on board).

Quick information:

Pyrotechnic Visual Distress Signals (flares, smoke signals, rockets and etc.) 
- required to carried upon by the Coast Guard 
-choices include varieties of red handheld or aerial flares for day and for night use






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in a square garden plot (with an area of 400 sq ft)deer fencing priced at $1.50 per foot is to be installed around the plot. if
mina [271]

We have a square garden of 400 square foot.

The area of a square is:

A=x^2

where x: side length.

In this case:

\begin{gathered} A=400=x^2 \\ x=\sqrt[]{400}=20\text{ ft} \end{gathered}

The perimeter of the square is the sum of the lengths of the sides of the square. As they are all equal, we can write:

P=4x=4\cdot20=80\text{ ft}

The fencing is priced at $1.50 per foot. If we add the 7% sales tax to this price we get:

C=1.50\cdot(1+0.07)=1.50\cdot1.07=1.605\text{ \$/ft}

The fencing will be installed in all the perimeter (80 ft).

We can calculate the total cost by multiplying the sales price ($1.605 per foot) and the perimeter (80 ft):

F=C\cdot P=1.605\frac{\text{\$}}{\text{ft}}\cdot80\text{ ft}=\$128.40

Answer: the fencing will cost a total of $128.40

8 0
1 year ago
The button on ernestos shirt has a diameter of 8 millimeters.what is the buttons radius
erma4kov [3.2K]

Answer:

4 mm

Step-by-step explanation:

The radius is half the diameter, so in this case the radius of each button is 4 mm.

5 0
3 years ago
Read 2 more answers
Based on the work shown on the left, what is the simplest form of StartRoot StartFraction 250 c cubed Over 9 d Superscript 6 Bas
Gnoma [55]

Answer:

It's A on E2020;  StartRoot StartFraction 250 c cubed Over 9 d Superscript 6 Baseline EndFraction EndRoot

Step-by-step explanation:

bleh

6 0
3 years ago
Read 2 more answers
Sorting through unsolicited e-mail and spam affects the productivity of office workers. An InsightExpress survey monitored offic
nydimaria [60]

Answer:

1. Refer to the explanation for the frequency table.

2. (a) 60%

   (b) 25%

Step-by-step explanation:

Part 1. The question is asking us to group the data according to the classes given and fill in the frequency (F), relative frequency (RF), cumulative frequency (CF) and relative cumulative frequency (RCF).

To compute the frequency for each class count the number of data that lies in the class range and write it. For the first class (1-5) we can see that there are 12 numbers which lie in the range 1 to 5. Those numbers are: 2, 4, 4, 1, 2, 1, 5, 5, 5, 3, 4, 4. Similarly, for the second class, the frequency is 3 because 8, 8, 8 lie in this range from our existing data. For the third class 11-15 there are 2 numbers in the given data which lie in this range and those numbers are 12, 15. Similarly, the rest of the frequencies can be computed.

For the relative frequency, the frequency of each class is divided by the total frequency i.e. 20.  

For the class 1-5, RF = 12/20 = 0.6.  

For 6-10, RF = 3/20 = 0.15

For 11-15, RF = 2/20 = 0.1

For 16-20, RF = 1/20 = 0.05

For 21-25, RF=1/20 = 0.05

For 26-30, RF = 0/20 = 0.00

For 31-34, RF= 1/20 = 0.05.

To compute the cumulative frequency, add the existing frequency of each class with the previous frequencies.

For 1-5, CF = 0+12 = 12

For 6-10, CF = 12+3=15

For 11-15, CF = 12+3+2 = 17

For 16-20, CF=12+3+2+1 = 18

For 21-25, CF = 12+3+2+1+1=19

For 25-30, CF = 12+3+2+1+1+0=19

For 31-34, CF = 12+3+2+1+1+0+1=20

Now, to compute relative cumulative frequency, add the existing relative frequency of each class with the previous relative frequencies.  

For 1-5, RCF = 0+0.6

For 6-10, RCF = 0.6 + 0.15 = 0.75

For 11-15, RCF = 0.6+0.15+0.1 = 0.85

The rest of the relative cumulative frequencies can be computed in the same way.

Class(Minutes)           F       RF     CF     RCF

      1-5                       12     0.60    12     0.60  

      6-10                      3     0.15     15     0.75  

      11-15                      2     0.10     17     0.85  

      16-20                    1      0.05    18     0.90  

      21-25                    1      0.05    19     0.95  

      26-30                   0     0.00    19     0.95  

      31-34                     1     0.05    20       1  

       <u>Total                  20</u>  

Part 2. Now, we are asked to compute the Ogive graph which is also called as the cumulative frequency graph. The cumulative frequency needs to be plotted on the y-axis and the upper limit of each class needs to be plotted on the x-axis. The graph is attached.

(a) From the graph we can see that the number of workers who spend less than 5 minutes on unsolicited e-mail and spam are 12. So the answer for this part is 12 workers.

Percentage = 12/20 x 100 = 60%

(b) From the graph we can see that the number of workers who spend less than 10 minutes on spam e-mail are 15. The question is asking for the number of people who spend more than 10 minutes. For this we need to subtract 15 from the total number of workers.  

Number of workers spending more than 10 minutes = 20-15 = 5 workers.

Percentage = 5/20 x 100 = 25%

4 0
3 years ago
YALL so im bored hmu <br> whats 420 - 22 tho
ozzi

Answer:

398

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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