Let p be
the population proportion. <span>
We have p=0.60, n=200 and we are asked to find
P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60
and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is
considered to be large and hence the sampling distribution of sample
proportion-^p will follow the z standard normal distribution. Hence this
sampling distribution will have the mean of all sample proportions- U^p = p =
0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] =
√[0.60*(1-0.60)/200] = √0.0012.
So, the probability that the sample proportion
is less than 0.58
= P(^p<0.58)
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0...
= P(z<-0.58)
= P(z<0) - P(-0.58<z<0)
= 0.5 - 0.2190
= 0.281
<span>So, there is 0.281 or 28.1% probability that the
sample proportion is less than 0.58. </span>
9514 1404 393
Answer:
(A) -2, 3/7, 1/2, 1.2
Step-by-step explanation:
The numbers are in increasing order when they are listed left-to-right as they appear on the number line.
The only numbers that may give you trouble are 3/7 = 6/14 and 1/2 = 7/14.
The negative number is less than any positive number. 1.2 is greater than any fraction that is less than 1.
The correct ordering is found in choice A.
The answer is 64.4 because you multiply 92 times 0.7 and get 64.4
Answer:
(-3x²- 9x+5) - (-2x²-4x +7)
= (-3x²- 9x²+5) (2x²+4x +7)
=-3x²-9x+5+2x²+4x-7
=-3x²+2x²-9x+4x+5-7
=-x²-5x-2
