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2 years ago

7

idc what your answer is. as long as it is related to the problem and makes sense, its based off of your opinion. (2 attachments,

4 problems)

1 answer:

PilotLPTM [1.2K]2 years ago

5 0

Answer:B

Step-by-step explanation:

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I need help with this please

Natali [406]

Answer:

the bottom answer choice : segment TD

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A bag contains 3 red,4 green, and 5 blue marbles. Three marbles are drawn at random. What is the probability that all three are

Reptile [31]

Answer:

1/22

Step-by-step explanation:

assuming that the marbles drawn are not replaced:

P(red) = 3/12 or 1/4

P(green) = 4/11

P(blue) = 5/10 or 1/2

multiply the probabilities together:

1/4 x 4/11 x 1/2 = 1/22

8 0

3 years ago

Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4

steposvetlana [31]

$f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}$

$\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}$

6 0

4 years ago

Read 2 more answers

What are the next two numbers in the sequence: 0.5, 1.0, 2.0, 4.0..... *

Ivanshal [37]

Answer:

8.0, 16.0

Step-by-step explanation:

times the before number by itself

8 0

3 years ago

Tell if I was right, and I'll thank you and mark you as branliest

PtichkaEL [24]

It is my opinion that it is C) but i am not sure, you might be correct though...

8 0

3 years ago