All categories

2 years ago

Simplify 3√20/√5 a)25/4 b)6 c)√5/5 d2√3/15

Mathematics

1 answer:

Blizzard [7]2 years ago

3 0

3√20/√5
= 3 √4 √5 / √5
= 3 * 2
= 6

answer is b)6

You might be interested in

Name the expression

Ivenika [448]

Answer:

since 7 is raised to the power 0 the answer is

a) linear polynomial with zero terms

8 0

2 years ago

Graph the image of the given triangle under a dilation with a scale factor of 1/4 and center of dilation (0, 0)

schepotkina [342]

Answer:

The image in the attached figure

Step-by-step explanation:

we know that

The dimensions of the image of the given triangle are equal to the original dimensions of the pre-image multiplied by the scale factor

In this problem the scale factor is 1/4

The height of the pre-image is 4 units

The base of the pre-image is 8 units

Find out the dimensions of the image

The height of the image is $(4)\frac{1}{4}=1\ unit$

The base of the image is $(8)\frac{1}{4}=2\ units$

The image in the attached figure

6 0

3 years ago

A state park is designed in a circular pattern as shown. A park ranger drives along the circular path from the ranger station to

Alex777 [14]

HOPE THIS HELPS U
Given:Ranger Station to Nature Center = 90°Nature Center to petting zoo = 40°Petting Zoo to Tennis Court = 120°Tennis Court to Pool = 65°Pool to Ranger Station = 45°radius = 1 mile
arc length = 2πr angle/360°
Ranger station to nature center.
arc length = 2 * 3.14 * 1 mile * 90°/360°arc length = 2 * 3.14 * 1 mile * 0.25arc length = 1.57 miles
Nature center to Petting Zoo
arc length = 2 * 3.14 * 1 mile * 40°/360°arc length = 2 * 3.14 * 1 mile * 0.11arc length = 0.70 miles
1.57 miles + 0.70 miles = 2.27 miles or 2.3 miles CHOICE B

7 0

2 years ago

In a set of 25 aluminum castings, four castings are defective (D), and the remaining twenty-one are good (G). A quality control

lianna [129]

Answer:

The sample space for selecting the group to test contains 2,300 elementary events.

Step-by-step explanation:

There are a total of N = 25 aluminum castings.

Of these 25 aluminum castings, n₁ = 4 castings are defective (D) and n₂ = 21 are good (G).

It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!(n-k)!}$

Compute the number of samples that are possible as follows:

${25\choose 3}=\frac{25!}{3!\times (25-3)!}$

$=\frac{25\times 24\times 23\times 22!}{3!\times 22!}\\\\=\frac{25\times 24\times 23}{3\times 2\times 1}\\\\=2300$

The sample space for selecting the group to test contains 2,300 elementary events.

6 0

2 years ago

Heeeeeeeeeeeeeeeeelp

lys-0071 [83]

Answer:

a b

Step-by-step explanation:

7 0

2 years ago