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2 years ago

Evaluate st2 - pqr, if p = -2, q = 5, r = -7, s = 0, and t = 4.

Mathematics

2 answers:

Pavel [41]2 years ago

6 0

Answer:

Step-by-step explanation:

st²-pqr

p= -2,q=5,r= -7,s=0 and t=4

(0)(4)²-(-2)(5)(-7)

16-(70)

16-70

=-54

Airida [17]2 years ago

4 0

Hey mate,

We have,

st²-pqr

Given values,

p= -2,q=5,r= -7,s=0 and t=4

On substituting,we obtain:

→(0)(4)²-(-2)(5)(-7)

→16-(70)

→16-70

→-54

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2 years ago

Read 2 more answers

one third of a land is on maize, a fifth of the remainder is on potatoes and the rest which is 0.5 ha is on beans. how much of t

disa [49]

Answer: $1250\ m^2$

Step-by-step explanation:

Let x= Total land.

Then for Maize = $\dfrac{x}{3}$

For Potatoes = $\dfrac15(x-\dfrac {x}{3})=\dfrac15(\dfrac{2x}{3})=\dfrac{2}{15}x$

For beans = $x- (\dfrac{x}{3}+\dfrac{2}{15}x)=0.5 \ ha$

$\Rightarrow\ x- (\dfrac{5x+2x}{15})=0.5 \ ha\\\\\Rightarrow\ x- (\dfrac{7x}{15})=0.5 \ ha\\\\\Rightarrow\ \dfrac{15x-7x}{15}=0.5 \ ha\\\\\Rightarrow\ \dfrac{8x}{15}=0.5 \ ha\\\\\Rightarrow\ x=0.5\times\dfrac{15}{8} \ ha\\\\\Rightarrow\ x=0.9375 \ ha$

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0.9375 ha = 9375 m²

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Hence, $1250\ m^2$ of the land is on potatoes.

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