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KiRa [710]
4 years ago
10

This is easy i don’t know it tho

Mathematics
2 answers:
Ede4ka [16]4 years ago
7 0

Answer:

5 in total

Step-by-step explanation:

Ipatiy [6.2K]4 years ago
6 0
It's asking you to count the corners.
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What is the percent increase from $399.00 to $535.00?? I WILL MARK YOU AS BRAINLIEST
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The answer should be 34.09%
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\frac{3}4 of 540 is \frac{3\cdot540}4=405 miles. Those will hence be traveled in \frac{405}{45}=\boxed{9\text{ hours}}
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One week, Moussa earned $273.00 at his job when he worked for 13 hours. If he is paid the same hourly wage, how many hours would
Anarel [89]

Answer:

18 hours

Step-by-step explanation:

Hello!

Let x equal the amount of money Moussa earns per hour of work.

Let y equal the number of hours Moussa works.

Given the one week where he earned $273 for working 13 hours, we can find the amount of money earned per hour of work.

<h3>Solve</h3>
  • 273 = 13x
  • 273/13 = x
  • 21 = x

Moussa earns $21 per hour.

We are now asked to find how many hours it will take to earn $378.

We can create an equation and solve.

<h3>Solve</h3>
  • 21y = 378
  • y = 378/21
  • y = 18

Moussa needs to work 18 hours to earn $378.

4 0
2 years ago
A sign says that the price marked on all music equipment is 35% off the original price. You want to buy an electric guitar for t
zaharov [31]

Step-by-step explanation:

c=p-0.35p

If the guitar is 315 dollars, then the price with discount is 204.75

8 0
4 years ago
Use Green's Theorem to evaluate the line integral along the given positively oriented curve. C 3y + 5e x dx + 8x + 9 cos(y2) dy
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By Green's theorem,

\displaystyle\int_C(3y+5e^x)\,\mathrm dx+(8x+9\cos(y^2))\,\mathrm dy

\displaystyle=\iint_D\left(\frac{\partial(8x+9\cos(y^2))}{\partial x}-\frac{\partial(3y+5e^x)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=5\iint_D\mathrm dx\,\mathrm dy

where D is the region enclosed by C. Equivalently, the line integral is equal to 5 times the area of D, which is

\displaystyle5\iint_D\mathrm dx\,\mathrm dy=5\int_0^1\int_{x^2}^{\sqrt x}\mathrm dy\,\mathrm dx=5\int_0^1(\sqrt x-x^2)\,\mathrm dx=\boxed{\frac53}

7 0
4 years ago
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