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julia-pushkina [17]
1 year ago
13

What is the slope of the line segment? 1 over 4 Negative 1 over 4 4 −4

Mathematics
1 answer:
solmaris [256]1 year ago
7 0
I think it’s 4 because every one across it goes up on 4
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(02.03)
RoseWind [281]

Answer:

It's the one under the one you have selected.

Step-by-step explanation:

7:2

14:4

28:8

56:16

Divide the first number by 7 then multiply it by 2.

Example: 56/7=8, 8*2=16 so it's correct.

4 0
2 years ago
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What is the standard form equation of 4x+7¥=11
yaroslaw [1]

This equation is in standard from unless you mean vertex standard form?  

5 0
2 years ago
Find the slope of the line that contains the following pair of points. (3, 4) (3, -7)
mojhsa [17]
Negative 3 is the answer
8 0
3 years ago
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Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
Mazyrski [523]

We can use the fact that, for |x|,

\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n

Notice that

\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1{1-x}\right]=\dfrac1{(1-x)^2}

so that

f(x)=\displaystyle\frac5{(1-x)^2}=5\frac{\mathrm d}{\mathrm dx}\left[\sum_{n=0}^\infty x^n\right]

f(x)=\displaystyle5\sum_{n=0}^\infty nx^{n-1}

f(x)=\displaystyle5\sum_{n=1}^\infty nx^{n-1}

f(x)=\displaystyle5\sum_{n=0}^\infty(n+1)x^n

By the ratio test, this series converges if

\displaystyle\lim_{n\to\infty}\left|\frac{(n+2)x^{n+1}}{(n+1)x^n}\right|=|x|\lim_{n\to\infty}\frac{n+2}{n+1}=|x|

so the series has radius of convergence R=1.

5 0
2 years ago
( − 35 − 42 − 63 ) ∶ ( + 7 )
olga nikolaevna [1]

(-35-42-63)/7= (-140)/7=-20

7 0
2 years ago
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