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lana66690 [7]
3 years ago
13

Luke records Jesus' visit to Jerusalem when He was twelve years old for the Feast of the

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0
Passover extra words to make 20 characters lol

     



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a botanist was measuring how tall her plant grew. after two weeks it had grown 9.62 inches. the second week alone it had grown 3
Elanso [62]

Answer:

6.5 inches

Step-by-step explanation:

Take the total 9.62 inches

Remove the 3.12 inches from the second week and there is your answer!

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A shower uses 12 gallons of water in 3 minutes. Complete the table and graph.
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That would be 4 gallons every minute!


Also: I don't see a graph..? Is there supposed to be one attached?

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The copy machine runs for 20 seconds and then jams. About how many copies were made before the jam occurred? Round your answer t
dangina [55]

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10.7

Step-by-step explanation:

7 0
3 years ago
Find each quotient and express it in rectangular form.
uranmaximum [27]

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A. thats the answer

Step-by-step explanation:

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4 0
2 years ago
Since at t=0, n(t)=n0, and at t=∞, n(t)=0, there must be some time between zero and infinity at which exactly half of the origin
Airida [17]
Answer: t-half = ln(2) / λ ≈ 0.693 / λ

Explanation:

The question is incomplete, so I did some research and found the complete question in internet.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

Answer:

1) Equation given:

N(t)=N _{0} e^{-  \alpha  t} ← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N_{t-half} =  N_{0} /2 =  N_{0}  e^{- \alpha t}

3) Solving for α (remember α is λ)

\frac{1}{2} =  e^{- \alpha t} 

2 =   e^{ \alpha t} 

 \alpha t = ln(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ




4 0
3 years ago
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