To determine the maximum value of a quadratic function opening downwards, we are going to find the vertex; then the y-value of the vertex will be our maximum.
To find the vertex (h,k) (where h=x-coordinate and k=y-coordinate) of a quadratic function of the form

we'll use the vertex formula:

, and then we are going to replace that value in our original function to find k.
So, in our function

,

and

.
Lets replace those values in our vertex formula:



Now that we know the x-coordinate of our vertex, lets replace it in the original function, to get the y-coordinate:



We just prove that the vertex of

is (2,1), and for the graph we can tell that the vertex of

is (-2,4). The only thing left is compare their y-coordinates to determine w<span>hich one has the greater maximum value. Since 4>1, we can conclude that </span>

has the greater maximum.
Step-by-step explanation:
Equation of a straight line
y = mx + c, m is the slope, and c the intercept
points (3,7) x = 3, y = 7, c = 1
7 = m × 3 + 1
7 = 3m + 1
3m = 7 - 1
3m = 6
m = 6/3
m = 2
2x + y = 17
To solve for y, subtract 2x from both sides;
y = 17 - 2xTo solve for x, subtract y from both sides;
2x = 17 - y
Divide both sides by 2;

Remark
The general equation for the point slope form is
(y - h) = slope(x - k)
<em><u>Givens</u></em>
given point = (5,7) from which
h = 7
k = 5
slope = m = - 13
Equation
(y - 7) = -13(x - 5) Usually the equation is left like this.