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faust18 [17]
3 years ago
8

Please help. I’ll mark you as brainliest if correct!!!!!

Mathematics
2 answers:
Semenov [28]3 years ago
6 0

Answer:

x^2+14x+40=0\\x^2+14x+40+9-9=0\\x^2+14x+49=9\\(x+7)^2=9\\\\D=7\\E=9

Step-by-step explanation:

SCORPION-xisa [38]3 years ago
5 0

x^2+14x+40=0\\x^2+14x+40+9-9=0\\x^2+14x+49=9\\(x+7)^2=9\\\\D=7\\E=9

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HELP ME PLEASEEE [GIVING BRAINLIEST TO BEST ANSWER W/ EXPLANATION]
vivado [14]

Answer:

Step-by-step explanation:

1. There is a total of 16 outcomes

2. To get outcomes with a sum GREATER than 5, we have

2+4, 3+3, 3+4, 4+2, 4+3, 4+4 for a total of 6 outcomes.

3. To spin the same number twice, the possible outcomes are

1-1, 2-2, 3-3, 4-4 for a total of 4 outcomes.

7 0
3 years ago
Of 125 students in 5th grade, 3/5 of them have a mobile phone. How many students do not have a mobile phone?
Annette [7]

Answer:75

Step-by-step explanation:125÷ 5=25

25*3=75

5 0
4 years ago
Read 2 more answers
Solve for x 12x/5 a.x=-71/2 b. x=71/2 c. x= 43 1/5
babunello [35]

Answer:

x  = - 12 6/7

Step-by-step explanation:

x - 12x/5= 18

Get a common denominator on the left

5/5 x -12/5x = 18

Subtract

-7/5 x = 18

Multiply each side by -5/7 to isolate x

-5/7 *-7/5 x = -5/7 *18

x = -5*18/7

x = -90/7

Changing this to a mixed number

7 goes into 90   1 2 times with 6 left over

x  = - 12 6/7


8 0
3 years ago
Read 2 more answers
A comedy show sells lower level tickets for $77 and upper level tickets for $99. On the opening night 2615 tickets were sold for
babunello [35]

Let x represent lower level tickets that cost $77

Let y represent upper level tickets that cost $99

Cost equation: 77x + 99y = 247,071

Tickets equation: x + y = 2615

Using the elimination method, multiply the second equation by -77:

77x + 99y = 247,071

-77x - 77y = -201,355

--> 22y = 45,716

--> y = 2,078

Now plug "y" into either equation and solve for "x". I chose the Tickets equation. x + y = 2615 → x = 2615 - y → x = 2615 - 2078 → x = 537

Answer: lower level = 537 tickets, upper level = 2078 tickets.


7 0
4 years ago
Read 2 more answers
Please help. 15 points! Two cards are randomly chosen, one at time, from a standard deck of 52 playing cards without replacement
lesya692 [45]
|\Omega|=52\cdot51=2652\\
|A|=4\cdot3=12\\\\
P(A)=\dfrac{12}{2652}=\dfrac{1}{221}\approx0.5\%
5 0
4 years ago
Read 2 more answers
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