<h3>Given</h3>
... 4 - |2x -1| = -3
<h3>Find</h3>
... x
<h3>Solution</h3>
Add |2x-1|+3
... 7 = |2x-1|
This resolves to two equations:
... -7 = 2x-1
... -6 = 2x
... -3 = x
and ...
... 7 = 2x -1
... 8 = 2x
... 4 = x
The two solutions are x = -3 and x = 4.
Answer:
c=5
Step-by-step explanation:
using pythagorean theorem, 3 squared plus 4 squared is 25. by finding square root of 25, you get 5
Answer:
First member-> 1 -> "1 one"
Second member-> 11 -> "2 ones"
Third member-> 21 -> "1 two, 1 one"
Fourth member -> 1211 -> "1ones, 1 two, 2 ones"
Fifth member-> 111221 -> "3 ones, 2 twos, 1 ones"
Sixth member-> 312211 -> "1three, 1 one, 2 twos, 2 ones"
Seventh member-> 13112221 ->" 1 one, 1 three, 2 ones, 3 twos, 1 one"
Step-by-step explanation:
Answer:
a = 2/27
b = 13/27
Step-by-step explanation:
The given polynomial is presented as follows;
f(x) = a·x³ + b·x² + x + 2/3
Given that x + 3 is a factor, we have;
f(-3) = 0 = a·(-3)³ + b·(-3)² - 3 +2/3 = 0
-27·a + 9·b - 3 + 2/3 = 0
-27·a + 9·b = 7/3........(1)
Also we have
(a·x³ + b·x² + x + 2/3) ÷ (x + 2) the remainder = 5
Therefore;
a·(-2)³ + b·(-2)² + (-2) + 2/3 = 5
-8·a + 4·b - 2 + 2/3 = 5
-8·a + 4·b = 2 - 2/3 = 4/3........(2)
Multiplying equation (1) by 4/9 and subtracting it from equation (2), we have;
-8·a + 4·b - 4/9×(-27·a + 9·b) = 4/3 - 4/9 × 7/3
-8·a + 12·a = 8/27
4·a = 8/27
a = 2/27 ≈ 0.0741
imputing the a value in equation (1) gives;
-27×2/27 + 9·b = 7/3
-2 + 9·b = 7/3
9·b = 7/3 + 2 = 13/3
b = 13/27 ≈ 0.481.
