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3 years ago

14

Cameron wants to buy six video games all costing the same amount he has a $30 coupon and he can spend no more than $100 write an

inequality to find the possible cost of each video game

2 answers:

Triss [41]3 years ago

7 0

Let's work this problem step by step, using each piece of given information to create the inequality:

Let x represent the cost of each video game that Cameron wants to buy. The price of the 6 games will be 6 multiplied with x, or 6x.

Cameron has a $30 coupon, which means that the price of the video games after the coupon will be 30 less than 6x, which is 6x - 30.

The last piece of information is that Cameron cannot spend any more than $100. Thus, the equation 6x - 30 must be less than or equal to 100.

Putting all this together, we can create the inequality:

$6x-30\leq 100$

If you need the inequality solved for x, let me know and I'll help you solve it

Also, let me know if you need any clarifications, thanks!

~ Padoru

P.S. Congrats on asking the 15 millionth question on Brainly!

7nadin3 [17]3 years ago

3 0

Answer:

x ≤ $21.66 which goes on forever

Step-by-step explanation:

<u>Step 1: Make an inequality</u>

6x - 30 ≤ 100

<u>Step 2: Solve for x</u>

6x - 30 + 30 ≤ 100 + 30

6x / 6 ≤ 130 / 6

x ≤ $21.666666666666666666666666666667

Answer: x ≤ $21.66 which goes on forever

You posted the 15 millionth question on Brainly. Congrats

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2 years ago

Find the Shaded Area:<br> 10 m<br> 10 m

Greeley [361]

Answer:

100-25pi m

Step-by-step explanation:

Let us subtract the circles area from the square

<em>First, let us find the area of the square:</em>

Base x height =

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<em>Now, the circle:</em>

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6 0

3 years ago

The 65 students in a classical music lecture class were polled, with the following results: 37 like Wolfgang Amadeus Mozart 36 l

Anna35 [415]

Answer:

a) 25

b) 30

c) 10

d) Not Mozart, 6

e) 2

Step-by-step explanation:

We use a Venn Diagram to solve this question.

I am going to say that:

A are the students who like Mozart.

B are the students who like Beethoven

C are the students who like Haydn.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a are those who only like Mozart, $(A \cap B)$ are those who like Mozart and Beethoven, $(A \cap C)$ are those who like Mozart and Haydn and $(A \cap B \cap C)$ are those who like all three of them.

By the same logic, we have that:

$B = b + (A \cap B) + (B \cap C) + (A \cap B \cap C)$

$C = c + (B \cap C) + (A \cap C) + (A \cap B \cap C)$

We start finding these values from the intersection:

8 like all three composers

This means that $A \cap B \cap C = 8$

14 like Beethoven and Haydn

This means that:

$(B \cap C) + (A \cap B \cap C) = 14$

So

$B \cap C = 6$

21 like Mozart and Haydn

This means that:

$(A \cap C) + (A \cap B \cap C) = 21$

Then

$A \cap C = 13$

14 like Mozart and Beethoven

This means that:

$(A \cap B) + (A \cap B \cap C) = 14$

$A \cap B = 6$

31 like Franz Joseph Haydn

This means that C = 31. So

$C = c + (B \cap C) + (A \cap C) + (A \cap B \cap C)$

$31 = c + 6 + 13 + 8$

$c = 4$

36 like Ludwig van Beethoven

This means that $B = 36$

So

$B = b + (A \cap B) + (B \cap C) + (A \cap B \cap C)$

$36 = b + 6 + 6 + 8$

$b = 16$

37 like Wolfgang Amadeus Mozart

This means that A = 37. Then

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

$37 = a + 6 + 13 + 8$

$a = 10$

a. exactly two of these composers?

$(A \cap B) + (A \cap C) + (B \cap C) = 6 + 13 + 6 = 25$

b. exactly one of these composers?

$a + b + c = 10 + 16 + 4 = 30$

c. like only Mozart?

$a = 10$

d. like Beethoven and Haydn, but not Beethoven?

I will use not Mozart.

So $B \cap C = 6$

Not Mozart, 6.

e. like none of these composers?

At least 1:

$(A \cup B \cup C) = a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 10 + 16 + 4 + 6 + 13 + 6 + 8 = 63$

The total is 65

So 65 - 63 = 2 like none of these composers

4 0

2 years ago

Need help with finding out what X is?

Marianna [84]

Answer:

Step-by-step explanation:

x + 4 = 2x + 1

-x -x

4 = 1x + 1

-1 -1

3 = 1x

-- --

1 1

3 = x

Check:

3 + 4 = 2(3) + 1

7 = 6 + 1

7 = 7

7 0

2 years ago