Answer:
Step-by-step explanation:
The minute hand of a clock overtakes the hour hand at intervalsof M minutes of correct time. The clock gains or loses in a day by=(720/11−M)(60×24/M) minutes.
Here M = 64. The clock gains or losses in a day by
=(720/11−M)(60×24/M)=(720/11−64)(60×24/64)
=16/11(60×3/8)=2/11(60×3)=360/11=32(8/11) minutes.
The area of a triangle can be calculated as half the product of base length and height. We want the area to be no greater than 10 in².
a) (1/2)(4)(2x-3) ≤ 10
b) 4x -6 ≤ 10 . . . . . simplify
... 4x ≤ 16 . . . . . . . .add 6
... x ≤ 4 . . . . . . . . . divide by the coefficient of x
c) The maximum value of (2x -3) in is (2·4 -3) in = 5 in.
The triangle should be no more than 5 in high to have an area less than 10 in².
Answer:
Y=⅘X+2. the picture not clear so i hesitate
Answer:
is goes to ¨¨not a function¨¨
Step-by-step explanation:
