Answer:
B, C, and E
Step-by-step explanation:
<u>Simplify all answer choices:</u>
A.
5(2x+10)+1=
10x+50+1=
10x+51
B.
7(x+2)+3x-3=
7x+14+3x-3=
10x+11
C.
3(3x+4)+x-1=
9x+12+x-1=
10x+11
D.
2(6x+4)+2x+5=
12x+8+2x+5=
14x+13
E.
2(6x+5)-2x+1=
12x+10-2x+1=
10x+11
Answer choices B, C, and E simplify to 10x+11
Answer:
0.44
Step-by-step explanation:
Given the estimated logistic regression model on risk of having squamous cell carcinoma
-4.84 + 4.6*(SMOKER)
SMOKER = 0 (non-smoker) ; 1 (SMOKER)
What is the predicted probability of a smoker having squamous cell carcinoma?
exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))
SMOKER = 1
exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)
exp^(-0.24) / (1 + exp^(-0.24))
0.7866278 / 1.7866278
= 0.4402863
= 0.44
Answer:
is one
Step-by-step explanation:
its just one i know trust me
Answer:
Aircraft carrier speed = 4.97 km/h
Step-by-step explanation:
Given that the time taken by the aircraft = 5 hours
Let the distance covered = X
Speed = V
Time taken by the ship = 7 hours
Let the distance covered = Y
Speed = 8V
Since it is 8 km/h faster than the aircraft carrier.
Using the speed formula
Speed = distance/time
Distance = speed × time
For the aircraft;
X = 5V
For the ship:
Y = 7 × 8V = 56V
Since they are 303km distance apart,
X + Y = 303
5V + 56V = 303
61V = 303
V = 303/61
V = 4.97 km/h
Aircraft carrier speed = 4.97 km/h
Answer:
I think it -1.50 to 10.58
Step-by-step explanation: