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3 years ago

$36.60 with the discount of 20%?

Mathematics

2 answers:

Semmy [17]3 years ago

8 0

Step-by-step explanation:

20% off of $36.60

= 80% of $36.60

= $36.60 * 0.8 = $29.28.

kenny6666 [7]3 years ago

4 0

Answer: $ $29.28$

Step-by-step explanation:

Question: $36.60 with the discount of 20%?

Steps:

Discount = Original Price * Discount %100

Discount = $36.6$ × $\frac{20}{100}$

Discount = $36.6$ × $0.2$

You save = $ $$7.32$

Final Price = Original Price - Discount

Final Price = $36.6 - 7.32$

Final Price = $ $29.28$

~I hope I helped :)~

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Kevin Horn is the national sales manager for National Textbooks Inc. He has a sales staff of 40 who visit college professors all

Oduvanchick [21]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

Given values:

$38, 40, 41, 45, 48, 48, 50, 50, 51, 51, 52, 52, 53, \\\\$ $54, 55, 55, 55, 56, 56, 57, 59, 59, 59, 62, 62, 62, \\ 63, 64, 65,66, 66, 67, 67, 69, 69, 71, 77, 78, 79, 79$

Total staff=40

In point a:

To calculate the median number first we arrange the value into ascending order and then collect the even numbers of calls that were also made. Its average of the middle terms is thus the median.

The midterms =55 and 59 so,

Median = $\frac{55+59}{2} = \frac{114}{2}=57$

In point b:

First-quarter $Q_1 = \frac{1}{4} \text{number of 8th call}$

$=\frac{1}{4} \times 30 th \\\\= 7.5 th$

The first quarterlies are $7.5th \ \ that \ is = (7+0.5)th\ \ term$

therefore the multiply of 0.5 by calculating the difference of the 7th and 8th term are:

$=0.5 \times 0= 0 \\\\\to Q_1 = 50+0=50 \\\\\to Q_3=\frac{3}{4} \text{number of 8th call} \\\\=\frac{3}{4} \times 30 th \\\\=22.5 \ th = (22+0.5)th \ \ term$

therefore the it is multiply by the 0.5 for the difference of the 22nd and 23rd term:

$= 0.5 \times 1=0.5 \\\\\to Q_3= 63+0.5=63.5$

In point c:

First decile $D_1 = \frac{1}{18} \text{number of 8th call}$

$= \frac{1}{10} \times 30 th \\\\= 3rd \ \ term\\\\\to D_1= 41 \\\\\to D_9= \frac{9}{10} \times 8\ th\ call\\\\=\frac{9}{10} \times 30 th \\\\=27th \ \ term\\\\\to D9 = 67$

In point d:

quartiles are:

$Q_1= 51.25 \\\\Q_3=66$

The right answers for the decile are:

$D_1=45.3 \\\\ D_9=76.4$

As for $D) P_{33} = 53.53$ will be available.

7 0

3 years ago

If z^2+1/z^2=11 , find the value of z^3-1/z^3,using only the positive value of z-1/z

vredina [299]

Hello,

Let's assume

$t=z- \dfrac{1}{z} \\\\

t^2=z^2-2+ \dfrac{1}{z^2}= 11-2=9==\ \textgreater \ t=3\\\\

t^3=z^3-3z^2* \dfrac{1}{z} +3z* \dfrac{1}{z^2} - \dfrac{1}{z^3} \\\\
=z^3 - \dfrac{1}{z^3} -3(z-\dfrac{1}{z})\\\\
z^3 - \dfrac{1}{z^3}=t^3+3t=3^3+9=27+9=36


$

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3 years ago

Solve this system of linear equations.separate the x- and y-value with a comma. -6x=-4-y -7x=-22+y.

scZoUnD [109]

Answer:

(2,8)

Step-by-step explanation:

Add them together to get rid of the y.

-6x = -4 - y

-7x = -22 + y

-13x = -26

Then solve for x.

-13x/-13 = -26/-13

x = 2

Now plug in the x value into either equation and solve for y.

-7(2) = -22 + y

-14 = -22 + y

-14 + 22 = -22 + 22 + y

8 = y

So...

x = 2

y = 8

(2,8)

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