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2 years ago

Can u plzz help me on this question

Mathematics

2 answers:

Kruka [31]2 years ago

8 0

Line of reflection is x=3. They overlap because the image crosses line of reflection.

Zigmanuir [339]2 years ago

7 0

Line is x=3 beuhhhhhhhh

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What does n/5 - 3n/10 =1/5

dsp73

I assume you're looking for n.
so, take 2n/10-3n/10=2/10. Making everything have the same denominator is always easier.

This way, you have -n/10=2/10.

n=-2.

8 0

3 years ago

Find the center and radius of this circle x^2+y^2-6x-10y+30=0

Artist 52 [7]

Answer:

Center: (3,5)

Radius: 2

Step-by-step explanation:

x² + y² - 6x - 10y + 30 = 0

Put equation into center-radius form. First regroup terms:

(x²-6x) + (y²-10y) = -30

Complete the squares:

(x²-6x+3²) + (y²-10y+5²) = -30 + 3² + 5²

(x-3)² + (y-5)² = 4 = 2²

Center: (3,5)

Radius: 2

8 0

2 years ago

The price of apples went down by $0.15 per pound. Kim bought 6 pounds of apples at the new price for a total of $8.88.

Tems11 [23]

Answer: (p x 6)+8.88= $9.78

Step-by-step explanation:

multiply 0.15 by 6

6 x 0.15= 0.90

add that to 8.88 and you get $9.78

hope this helps! ;P

7 0

2 years ago

A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

mestny [16]

Answer:

The value is $W= 2640 \ ft \cdot lb$

Step-by-step explanation:

From the question we are told that

The weight of the bucket is $F = 5 lb$

The depth of the well is $x_1 = 60 \ ft$

The weight of the water is $W_w = 42 lb$

The rate at which the bucket with water is pulled is $v = 1.5 \ ft/s$

The rate of the leak is $r = 0.15 lb/s$

Generally the workdone is mathematically represented as

$W = \int\limits^{x_1}_{x_o} {G(x)} \, dx$ ]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

$G(x) = F + (W_w- Ix)$

Here I is the rate of water loss in lb/ft mathematically represented as

$I = \frac{r}{v}$

=> $I = \frac{0.15 }{1.5 }$

=> $I = 0.1$

$G(x) = 5 + (42- 0.1x)$

=> $G(x) = 47- 0.1x)$

$W = \int\limits^{60}_{0} {47- 0.1x} \, dx$ ]

=> $W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.$

=> $W= [47(60) - 0.05(60)^2]$

=> $W= 2640 \ ft \cdot lb$

7 0

3 years ago

Find the sum. 5 2a a? + 2a + 1 + a2 + 4a + 3

Salsk061 [2.6K]

$\frac{2a}{a^2+2a+1}+\frac{5}{a^2+4a+3}$

Factor the denominators.

$\frac{2a}{\left(a+1\right)^2}+\frac{5}{\left(a+1\right)\left(a+3\right)}$

Adjust fractions based on LCM.

$\frac{2a\left(a+3\right)}{\left(a+1\right)^2\left(a+3\right)}+\frac{5\left(a+1\right)}{\left(a+1\right)^2\left(a+3\right)}$

Denominators are same, so add the fractions.

$\frac{2a\left(a+3\right)+5\left(a+1\right)}{\left(a+1\right)^2\left(a+3\right)}$

Expand the numerator.

$\frac{2a^2+11a+5}{\left(a+1\right)^2\left(a+3\right)}$

5 0

3 years ago

Read 2 more answers