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Leni [432]
2 years ago
8

Can u plzz help me on this question

Mathematics
2 answers:
Kruka [31]2 years ago
8 0
Line of reflection is x=3. They overlap because the image crosses line of reflection.
Zigmanuir [339]2 years ago
7 0
Line is x=3 beuhhhhhhhh
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Solve the quadratic equation for x. What is the product when the roots are multiplied? (x + 2)2 = 1 A) −3 B) −6 C) −9 D) 3
ehidna [41]

Answer:

D

Step-by-step explanation:

To solve the quadratic equation, use the inverse operation to squaring. This will undo the exponent and allows x to be isolated. The inverse operation is the square root. This is called the square root property of equality.

(x + 2)² = 1

√(x+2)² = √1

(x+2) = ±1

x = 1 -2     and   x = -1 - 2

x = -1        and   x = -3

The product of the roots -1 and -3 is -1*-3 = 3

8 0
2 years ago
There are 12 tennis racquets and 8 hockey sticks in a gym class. What percent of the gym equipment in the class are hockey stick
katrin2010 [14]
40% of the equipment in the class are hockey sticks

12+8=20
8/20 × 100=40
7 0
3 years ago
TEN POINTS !!!!! if f(x)=x^2-6x and g(x)=x^3 squared what is (fog) (x)
Elena L [17]

Answer:

f(x) = x² - 6x

g(x) = (x³)² = x^6

( f o g) x

Wherever you see x in f(x) replace it by g(x)

That's

( f o g)(x) = (x^6)² - 6(x^6)

= x^12 - 6x^6

Hope this helps

5 0
3 years ago
Suppose you have $15,000 in equipment for your business. You expect
Margarita [4]
I am stuck on this too
6 0
3 years ago
An airplane has 100 seats for passengers. Assume that the probability that a person holding a ticket appears for the flight is 0
zmey [24]

Answer:

96.33% probability that everyone who appears for the flight will get a seat

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 105, p = 0.9

So

\mu = E(X) = np = 105*0.9 = 94.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{105*0.9*0.1} = 3.07

What is the probability that everyone who appears for the flight will get a seat

100 or less people appearing to the flight, which is the pvalue of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 94.5}{3.07}

Z = 1.79

Z = 1.79 has a pvalue of 0.9633

96.33% probability that everyone who appears for the flight will get a seat

7 0
2 years ago
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