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andrew11 [14]
3 years ago
5

What is the y-intercept of the line with a slope of − 1/4 that passes through the point (−2, −9/2 )?

Mathematics
2 answers:
svlad2 [7]3 years ago
4 0
-9/2 = -1/4(-2)+ b

-9/2 = 1/2 + b
Minus 1/2 over

B= -5

Hope this helps!
Sladkaya [172]3 years ago
4 0

\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{-\frac{9}{2}})~\hspace{10em} slope = m\implies -\cfrac{1}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\left( -\cfrac{9}{2} \right)=-\cfrac{1}{4}[x-(-2)] \\\\\\ y+\cfrac{9}{2}=-\cfrac{1}{4}(x+2)\implies y+\cfrac{9}{2}=-\cfrac{1}{4}x-\cfrac{1}{2}\implies y=-\cfrac{1}{4}x-\cfrac{1}{2}-\cfrac{9}{2}

\bf y=-\cfrac{1}{4}x-\cfrac{10}{2}\implies y=-\cfrac{1}{4}x\stackrel{\stackrel{b}{\downarrow }}{\boxed{-5}}\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

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4 0
3 years ago
Elimination method: ax+by=r, -bx+cy=s
Alex17521 [72]
\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]

Isolate x for ax+by=r

x= \frac{r-by}{a} ; a \neq 0

Subsititute x= \frac{r-by}{a}

-b \frac{r-by}{a} +cy=s

Isolate r for : -b \frac{r-by}{a}+cy=s

r=- \frac{as-acy-b^2y}{b} ; a \neq 0;b \neq 0

For x : \frac{r-by}{a}

Subsititute r = - \frac{as-acy-b^2y}{b}

x= -\frac{as-acy-b^2y}{b}/a

x =  \frac{cy-s}{b}

The solutions to the system of equations are:

r= -\frac{as-acy-b^2y}{b} and <span> x = \frac{cy-s}{b}
</span>
hope this helps!


3 0
3 years ago
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