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3 years ago

What is the area of this triangle?

Mathematics

2 answers:

Andrews [41]3 years ago

8 0

Answer:

21x square inches

Step-by-step explanation:

Area of triangle= 1/2(bh)

=1/2(7x(6x))

=1/2(42x)

=21x

11Alexandr11 [23.1K]3 years ago

3 0

Answer:42x

Step-by-step explanation:6x . 7x = 42x

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Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

4 years ago

Compute 7 2/3 + 8 1/2 + 4 1/6. which is the sum in simplified form\

kotegsom [21]

hope I'm right but either 2 or 4 i can kinda go either way

6 0

3 years ago

Read 2 more answers

If you are adding two fractions that are both greater than 1/2, what must be true about the sum? Give three examples to support

slavikrds [6]

Answer:

The sum must be greater than 1

Step-by-step explanation:

Two fractions that are greater than 1/2 let's say

Example 1

3/4 and 7/8, the sum will be

3/4+7/8 with LCM of denominator as 8 sum= $\frac {(3*2)+7}{8}=\frac {13}{8}=1\frac {5}{8}$ which is more than 1

Example 2

6/9 and 5/8 with the LCM of denominator as 72, the sum= $\frac {(6*8)+(5*9)}{72}=\frac {93}{72}=1\frac {7}{24}$ which is greater than 1

Example 3

8/9 and 7/9 with the LCM of denominator as 9, the sum= $\frac {8+7}{9}=\frac {15}{9}=1\frac {2}{3}$ which is greater than 1

3 0

4 years ago

Please Help will award brainliest

EastWind [94]

Answer:7

Step-by-step explanation:

Remember,

PEMDAS

Begin by 3 / 1/3 = 1

1+1=2

9-2 = 7

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20-%203%7D%20%2B%20%20%5Csqrt%7Bx%20%2B%205%7D%20%20%3D%204" id="TexFormula1" t

Nuetrik [128]

Answer:

x = 4

Step-by-step explanation:

√x-3 + √x+5 = 4

(√x-3)² = (4-√x+5)²

x-3 = 16 - 8√x+5 + x+5 | -x

- 3 = 21 - 8√x+5

- 24 = - 8√x+5 | ×(-1)

24 = 8√x+5 | : 8

3 = √x+5

3² = (√x+5)²

9 = x + 5

x = 4

3 0

3 years ago