Given BD and AC is a diameter of the circle:
We need to find the following:
1. measure of the arc BA
So,
the measure of the minor arc BA = 44
The measure of the major arc BA = 360 - 44 = 316
2. the measure of the arc ACB = 360 - 44 = 316
3. The arc BCD is a semicircle of the circle
So, the measure of the arc BCD = 180
Steps:
18 x 2
What is that?
You can also think of it as 9 x 4 if that is easier
Then whatever you got for that, add 21 then subtract 12 and add 1
Mason has 22 tickets now. You can know this because you divide 176 by 8
That looks like a rectangular prism
