All categories

2 years ago

34.75 divided by 5 equals what

Mathematics

2 answers:

Hoochie [10]2 years ago

5 0

Answer:

6.95

Step-by-step explanation:

irga5000 [103]2 years ago

3 0

It equals 6.95. By utilizing simple division we can solve this answer.

You might be interested in

3/4 < ?/12 fill in the missing number

Lelechka [254]

Answer:

Step-by-step explanation:

12 / 4 = 3

3 x 3 = 9

3 0

2 years ago

The numerator of a given fraction is 4 less than the denominator. if 3 is subtracted from the numerator and 5 is added to the de

Sergeu [11.5K]

Answer:

Step-by-step explanation:Given that the numerator of a given fraction is 4 less than its denominator.

Also given that 3 is subtracted from the numerator and 5 is added to the denominator, the fraction becomes one by fourth .

Let the fraction be

Since the numerator of a given fraction is 4 less than its denominator we have,

Numerator=Denominator-4

⇒ a=b-4

Since 3 is subtracted from the numerator and 5 is added to the denominator, the fraction becomes one by fourth we have

4(a-3)=1(b+5)

4a-12=b+5

4a-b=17

4(b-4)-b=17 ( ∵ a=b-4)

4b-16-b=17

3b=17+16

3b=33

⇒ b=11

Now put b=11 in a=b-4 we get

a=11-4

⇒ the fraction is a/b=7/11

3 0

2 years ago

Add c to b, then subtract 6 from the result

Arisa [49]

Answer:

Their was not enough recourses for me to work with i am sorry next time be more specific

Step-by-step explanation:

5 0

2 years ago

1.172 as a percentage?

hodyreva [135]

Answer: 117.2%

Step-by-step explanation:

Multiply both numerator and denominator by 100. We do this to find an equivalent fraction having 100 as the denominator.

Multiply both numerator and denominator by 100. We do this to find an equivalent fraction having 100 as the denominator.

= (1.172 × 100) × 1/100=117.2/100

Write in percentage notation: 117.2%

8 0

2 years ago

Read 2 more answers

An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so

alexgriva [62]

Solution :

Let $p_1$ and $p_2$ represents the proportions of the seeds which germinate among the seeds planted in the soil containing $3\%$ and $5\%$ mushroom compost by weight respectively.

To test the null hypothesis $H_0: p_1=p_2$ against the alternate hypothesis $H_1:p_1 \neq p_2$ .

Let $\hat p_1, \hat p_2$ denotes the respective sample proportions and the $n_1, n_2$ represents the sample size respectively.

$$\hat p_1 = \frac{74}{155} = 0.477419$

$n_1=155$

$$p_2=\frac{86}{155}=0.554839$

$n_2=155$

The test statistic can be written as :

$$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}$

which under $H_0$ follows the standard normal distribution.

We reject $H_0$ at $0.05$ level of significance, if the P-value or if $|z_{obs}|>Z_{0.025}$

Now, the value of the test statistics = -1.368928

The critical value = $\pm 1.959964$

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

$=2 \times 0.085667$

= 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$ , so we fail to reject $H_0$ at $0.05$ level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the $\text{proportion}$ of the seeds that $\text{germinate differs}$ with the percent of the $\text{mushroom compost}$ in the soil.

8 0

2 years ago