All categories

3 years ago

What number would complete the pattern below? 66 73 13 21 52 __ 10 20

Mathematics

2 answers:

ipn [44]3 years ago

4 0

D. 61 is the answer thats the number that would complete the pattern

Serhud [2]3 years ago

3 0

The answer is d.61. 66+7=73. 13+8=21. 52+9=61. 10+10=20

You might be interested in

The perimeter of the warehouse can be modeled by which of the following?

Irina18 [472]

Answer one, and it is correct.

6 0

4 years ago

Read 2 more answers

Which of the following is a geometric sequence with a common ratio of 2?

rosijanka [135]

The answer C.
Since the common ratio is 2
You just need to multiply each number with two to get the next number
14x2=28
28x2=56
56x2= 112

6 0

3 years ago

A craft show has an admission fee of $1.50 for children and $4.00 for adults. On Saturday 155 people came to the carnival and $5

rjkz [21]

X+y=155. Y= -x+155

1.50x +4(-x+155)= 520
1.50x-4x+620=520
-2.5x =-100
X= 40. Y=110

8 0

3 years ago

Find the diameter of the circle with the given circumference. Use 3.14 for pi. C=29 cm The diameter is about ____ cm. (Round to

dezoksy [38]

Answer:

= 9.2 cm

Step-by-step explanation:

D = C ÷ π

= 29cm ÷ 3.14

= 9.2356

= 9.2 cm

4 0

3 years ago

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

5 0

3 years ago