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Mandarinka [93]
1 year ago
10

JK = (2x + 42) and KL = (30 - 2x). If K is between J and L. find JL

Mathematics
1 answer:
e-lub [12.9K]1 year ago
6 0

If K is between J and L. Then:

JK +KL = JL

Since:

JK = (2x + 42) and KL = (30 - 2x)

Replacing and adding:

(2x + 42) + (30 - 2x)

2x+42+30-2x

2x-2x+24+30

54

JL =54

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Complete the point-slope equation of the line through (6,4)and (7,2)
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Read 2 more answers
Simplify the following expression.
Blababa [14]

Answer:

-6x

Step-by-step explanation:

I just answered this

it will equal -6x

good luck :)

5 0
4 years ago
Identify the error below. Then, solve the equation correctly.
lions [1.4K]

Answer:

Error: +3x should be -3x

x should equal 3

Step-by-step explanation:

In this problem, you have to pay attention how values are transferred from one side to the other. This includes paying attention t the signs.

In 3x + 4 = 8x - 11, you want to try an keep all the values positive

      3x   +   4   =   8x  -   11

   <em> - 3x                - 3x</em>

                  4   =   5x  -   11

                 +11               +11      <--This part of the equation was correct.

                  15  =  5x

                  /5       /5   <--This part of the equation should result in dividing by <em>5</em>

                  3   =  x

Hope this helps!

3 0
3 years ago
Fill in the missing portions of the function to rewrite g(x) = 3a^2 − 42a + 135 to reveal the zeros of the function. What are th
Nikitich [7]

Answer:

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

g(x) = 3x^{2} - 42a + 135

So

a = 3, b = -42, c = 135

\bigtriangleup = (-42)^{2} - 4*3*135 = 144

x_{1} = \frac{-(-42) + \sqrt{144}}{2*3} = 9

x_{2} = \frac{-(42) - \sqrt{144}}{2*3} = 5

So

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

7 0
4 years ago
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