Complete question :
Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an
hourly rate of $28. The plumber only charges for a whole number of hours. Anand would like to spend no more than $250, and he wonders how many hours of work he can afford.
Let H represent the whole number of hours that the plumber works.
1) Which inequality describes this scenario?
Choose 1 answer:
A. 28 + 65H < 250
B. 28 + 65H > 250
C. 65 + 28H < 250
D. 65 +28H > 250
2) What is the largest whole number of hours that Anand can afford?
Answer:
65 + 28H < 250
Number of hours Anand can afford = 6 hours
Step-by-step explanation:
Given the following information :
Initial hourly rate = $65
Hourly rate = $28
Number of hours worked (whole number) = H
Maximum budgeted amount to spend = $250
Therefore ;
(Initial charge + total charge in hours) should not be more than $250
$65 + ($28*H) < $250
65 + 28H < 250
Number of hours Anand can afford :
65 + 28H < 250
28H < 250 - 65
28H < 185
H < (185 / 28)
H < 6.61
Sinve H is a whole number, the number of hours he can afford is 6 hours
The answer would be 4 x 4 = 16+14= 30
R u serious,
y=1/2x
graph at (0,0), and (10, 5)
clearly
ez.
Answer: 25/676
Step-by-step explanation:
Number of possible outcomes = 26
In other to win, one must draw must be either (A, E, I, O or U)
Therefore required drws to win = 5
First draw:
P(win) = Total required outcome / Total possible outcome
P(win) = 5/26
Second draw:
P(win) = Total required outcome / Total possible outcome
P(win) = 5/26
Therefore,
P(winning twice) = (5/26) × (5/26) = 25/676
50x+40=y for doors galore
40x+60=y for g&h
I can't graph here sorry but hopefully you know how that works
9. 40x+60=50x+40
-40
40x+20=50x
-40x
10x=20
x=2
10. Doors galore because 1 hours equates to 90 while g&h is 100 and so 90>100 then Doors galore is cheaper
thank you & if this helped pls don't forget to give brainiest
