Question

In the triangle below what ratio is sec H

Answer 1

For this case we have that by definition:

$Secant (A) = \frac {1} {Cosine (A)}$

Then, we find the cosine of the angle H, this will be given by the leg adjacent to H on the hypotenuse of the triangle.

$Cos (H) = \frac {g} {f}$

So, the secant of H is given by:$Sec {H} = \frac {1} {\frac {g} {f}}\\Sec {H} = \frac {f} {g}$

Answer:

Option C