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Vedmedyk [2.9K]
2 years ago
13

Helppppp math is my worst subject

Mathematics
2 answers:
galben [10]2 years ago
7 0
It's  x+4 over x+1 as a fraction.

Hope that helped :)
yarga [219]2 years ago
3 0
  well i got 
x+4/x+1
when i calculated it 


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What is the intersection of plane TUYX and plane VUYZ?
defon
Answer is UY Because they both connect her causing an intersection


3 0
2 years ago
Read 2 more answers
Triangle KNM is shown. Triangle K N M is shown. Angle M K N is 25 degrees. Angle K N M is 130 degrees. Angle N M K is 25 degrees
mars1129 [50]

Answer:

<h3>Two of the sides of triangle KNM are the equal</h3>

Step-by-step explanation:

From the triangle KNM, we can see that two of the angles M K N and Angle N M K are the same. If two of the angles are equal this means that two of the sides of the triangles are also equal. This type of triangle is known as an ISOSCELES TRIANGLE.

An isosceles triangle is a triangle that has two of its angles and sides to be equal.

6 0
2 years ago
(08.07 HC)
andreev551 [17]

Answer:

\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}

\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

C)  See attachment.

Step-by-step explanation:

Given function:

f(x)=2x^2-x-10

<h3><u>Part A</u></h3>

To factor a <u>quadratic</u> in the form  ax^2+bx+c<em> , </em>find two numbers that multiply to ac and sum to b :

\implies ac=2 \cdot -10=-20

\implies b=-1

Therefore, the two numbers are -5 and 4.

Rewrite b as the sum of these two numbers:

\implies f(x)=2x^2-5x+4x-10

Factor the first two terms and the last two terms separately:

\implies f(x)=x(2x-5)+2(2x-5)

Factor out the common term  (2x - 5):

\implies f(x)=(x+2)(2x-5)

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

\implies (x+2)(2x-5)=0

Therefore:

\implies (x+2)=0 \implies x=-2

\implies (2x-5)=0 \implies x=\dfrac{5}{2}

So the x-intercepts are:

x=-2, \:\:x=\dfrac{5}{2}

<h3><u>Part B</u></h3>

The x-value of the vertex is:

\implies x=\dfrac{-b}{2a}

Therefore, the x-value of the vertex of the given function is:

\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}

To find the y-value of the vertex, substitute the found value of x into the function:

\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}

Therefore, the vertex of the function is:

\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

<h3><u>Part C</u></h3>

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards.  This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>.  Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0
1 year ago
What is the midpoint of (-3,-7) and (9,8)
Sliva [168]
Hope this will help you. It is a little hard to explain.

4 0
3 years ago
What is the slope of the line that passes through the points (1, 3) and (5, –2)?
Sergeu [11.5K]

m=-(5/4)

From left to right, (1,3) is first and then comes (5,-2). Always remember when finding slopes without equations, the rule is RISE over RUN, to the numerator and denominator, respectively.

The y value of the second coordinates becomes negative which is unlike the y value in the first coordinates, which means our slope is downward, meaning it has a negative sign in front.

In every slope, there’s a numerator, being the rise, and a denominator, being the run.

To find the rise, we must look at the y values. Starting at 3 going to -2 has a space of 5 units, making that our numerator.

To find the run, the first x value is 1 and the second is 5, making a space of 4, which is out denominator.

With these two numbers and the negative sign, we get -(5/4) as our slope.

7 0
2 years ago
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