C = 1.6b
c + b = 442
1.6b + b = 442
2.6b = 442
b = 442 / 2.6
b = 170 <== Boston
c = 1.6b
c = 1.6(170)
c = 272 <== Colorado Springs
Answer:

Step-by-step explanation:
Hi there!
<u>What we need to know:</u>
- Linear equations are typically organized in slope-intercept form:
where m is the slope and b is the y-intercept (the value of y when x is 0) - Parallel lines always have the same slope
<u>1) Determine the slope of line S using line R (m)</u>

We can identify clearly that the slope of the line is
, as it is in the place of m. Because parallel lines always have the same slope, the slope of line S would also be
. Plug this into
:

<u>2) Determine the y-intercept of line S (b)</u>

Plug in the given point (-4,3) and solve for b

Subtract 1 from both sides to isolate b

Therefore, the y-intercept is 2. Plug this back into
:

I hope this helps!
Answer:
Skeptics
Step-by-step explanation:
my aunt is one and have a nice day :)
Answer:
5.66 inches
Step-by-step explanation:

a² + 7² = 9²
a² + 49 = 81
a² + 49 - 49 = 81 - 49
a² = 32
a = square root of 32
a = 5.6568 or 5.66 inches
I used the Pythagorean Theorem to solve this.
Answer:
F = 3x +(2.7×10^7)/x
Step-by-step explanation:
The formulas for area and perimeter of a rectangle can be used to find the desired function.
<h3>Area</h3>
The area of the rectangle will be the product of its dimensions:
A = LW
Using the given values, we have ...
13.5×10^6 = xy
Solving for y gives ...
y = (13.5×10^6)/x
<h3>Perimeter</h3>
The perimeter of the rectangle is the sum of the side lengths:
P = 2(L+W) = 2(x+y)
<h3>Fence length</h3>
The total amount of fence required is the perimeter plus one more section that is x feet long.
F = 2(x +y) +x = 3x +2y
Substituting for y, we have a function of x:
F = 3x +(2.7×10^7)/x
__
<em>Additional comment</em>
The length of fence required is minimized for x=3000. The overall size of that fenced area is x=3000 ft by y=4500 ft. Each half is 3000 ft by 2250 ft. Half of the total 18000 ft of fence is used for each of the perpendicular directions: 3x=2y=9000 ft.