Answer:
13 with a remainder of 44
Step-by-step explanation:
.
Given:
x, y and z are integers.
To prove:
If
is even, then at least one of x, y or z is even.
Solution:
We know that,
Product of two odd integers is always odd. ...(i)
Difference of two odd integers is always even. ...(ii)
Sum of an even integer and an odd integer is odd. ...(iii)
Let as assume x, y and z all are odd, then
is even.
is always odd. [Using (i)]
is always odd. [Using (i)]
is always even. [Using (ii)]
is always odd. [Using (iii)]
is always odd.
So, out assumption is incorrect.
Thus, at least one of x, y or z is even.
Hence proved.
17y-8=12+13y
4y=20
y=5
11x-4=117
11x=121
x=11
This is the answer, and I have steps, if have any questions, message me.