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Dimas [21]
3 years ago
15

Helppppppppppppppppp

Mathematics
2 answers:
bixtya [17]3 years ago
8 0
The answer is C. Good luck
DedPeter [7]3 years ago
7 0
A = 180 - 39
a = 141

b = 360 - (141 + 39 + 111)
b = 360 - 291
b = 69

answer is a. trapezoid, a = 141,  b = 69
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What is the missing term in the factorization?
wel

Answer:

100x^2-36=4(5x+3)(5x-3)

7 0
2 years ago
Follow the process of completing the square to solve 2x2 + 8x - 12 = 0.
Rom4ik [11]
Please:  Use "^" to denote exponentiation:  <span>2x^2 + 8x - 12 = 0

Reduce this by div. every term by 2:             </span><span>x^2 + 4x - 6 = 0

Here a=1, b=4 and c = -6.  Square half of b, obtaining (4/2)^2 = 4, and add, and then subtract, this 4 to x^2 + 4x - 6:

</span> x^2 + 4x +4  - 4 - 6 = 0.  Rewrite the square as (x+2)^2, obtaining new equation

(x+2)^2 = 10.  Take the sqrt of both sides:   x+2 = plus or minus sqrt(10).

Finally, solve for x:  x = -2 plus or minus sqrt(10).



8 0
3 years ago
is x-1 taking away an x or adding an x?? im trying to find the perimeter of area tiles, and the perimeter is x + x + x + (x-1) +
Vanyuwa [196]

Answer:

4x + 2

Step-by-step explanation:

x - 1 is adding an x and subtracting a 1 ,so

x + x + x + (x - 1) + 1 + 1 + 1

= x + x + x + x - 1 + 1 + 1 + 1 ← collect like terms

= 4x + 2

3 0
2 years ago
- 7 ( x - 2 ) + 1 = 15 - 7x
Savatey [412]

Answer: x=1

Step-by-step explanation:

You need to open up the parenthesis so you multiply every term inside the parenthesis by -7.

1.  -7x + 14 + 1 = 15 -7x

2. Combine like terms -7x + 15 = 15-7x

The two sides of the equation are the same so that means that x=1

5 0
3 years ago
Find the critical numbers of the function. (Enter your answers as a comma-separated list. Use n to denote any arbitrary integer
lyudmila [28]

If

f(\theta)=10\cos\theta+5\sin^2\theta

then the derivative is

f'(\theta)=-10\sin\theta+10\sin\theta\cos\theta

Critical points occur where f'(\theta)=0. This happens for

-10\sin\theta+10\sin\theta\cos\theta=0

-10\sin\theta(1-\cos\theta)=0

\implies-10\sin\theta=0\text{ or }1-\cos\theta=0

In the first case, we find

-10\sin\theta=0\implies\sin\theta=0\implies\theta=n\pi

In the second,

1-\cos\theta=0\implies\cos\theta=1\implies\theta=2n\pi

So all the critical points occur at multiples of \pi, or n\pi. (This includes all the even multiples of \pi.)

3 0
3 years ago
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