(a) First find the intersections of

and

:

So the area of

is given by

If you're not familiar with the error function

, then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.
(b) Find the intersections of the line

with

.

So the area of

is given by


which is approximately 1.546.
(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve

and the line

, or

. The area of any such circle is

times the square of its radius. Since the curve intersects the axis of revolution at

and

, the volume would be given by
Answer:
None (no solutions)
Step-by-step explanation:
-10q=-10q-7 (add 10q to both sides to get the costant 7 by itself)
-10q+10q=-10q+10q-7
0=-7 ( zero will never equal -7 hence there are no solutions to this equation)
Your answer would be 23.1
They answer would have to be 17+0=17