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Vadim26 [7]
3 years ago
9

Draw or write to explain why 1 hundred 4 tens and 14 tens name the same amount

Mathematics
1 answer:
Anastasy [175]3 years ago
5 0
To begin with, we are dealing with place value. For example, 158. 8, is in the ones place, 5 is in the tens place, and 1 is in the hundreds place. To write it out, this simply means 100 + 50 + 8. Referring back to your question, 1 hundred equals 100, and 4 tens equals 40. (Add those) 100 + 40 = 140.
One way to look at 14 tens is 14 x 10. Ten = 10, 14 (10) = 140. So 14 tens equals 1 hundred 4 tens because they both equal 140.
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If g is the inverse of the function f(x) = sqrt(x - 6) - 10 , which of the following is g?
iren2701 [21]

Answer:

  • g(x) = x² + 20x + 106

Step-by-step explanation:

<u>Given:</u>

  • f(x) =\sqrt{x-6}-10

If g(x) is the inverse of f(x), find it.

<u>Swap x with g(x) and f(x) with x:</u>

  • x =\sqrt{g(x)-6}-10

<u>Solve for g(x):</u>

  • x + 10 = \sqrt{g(x)-6}
  • (x+10)^2=g(x)-6
  • g(x) = x^2+20x + 100+6
  • g(x) = x^2+20x + 106

3 0
3 years ago
Shawna invests $5,048 in a savings account with a fixed annual interest rate of 4% compounded 12 times per year. How long will i
Elena-2011 [213]

Answer:

5 years

Step-by-step explanation:

In the question we are given;

  • Amount invested or principal amount as $5048
  • Rate of interest as 4% compounded 12 times per year
  • Amount accrued as $6,163.59

We are required to determine the time taken for the money invested to accrue to the given amount;

Using compound interest formula;

A=P(1+\frac{r}{100})^n

where n is the interest period and r is the rate of interest, in this case, 4/12%(0.33%)

Therefore;

6,163.59=5,048(1+\frac{0.333}{100})^n

1.221=(1+\frac{0.333}{100})^n

1.221=(1.0033)^n

introducing logarithms on both sides;

log1.221=log(1.0033)^n\\n=\frac{log1.221}{log1.0033} \\n=60.61

But, 1 year = 12 interest periods

Therefore;

Number of years = 60.61 ÷ 12

                            = 5.0508

                            = 5 years

Therefore, it will take 5 years for the invested amount to accrue to $6163.59

3 0
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