You have to use y=mx+b
so you plug it in 4=6(3)+b
subtract 18 from both sides
-14=b
b is the y-intercept so it would be .... y=6x-14
you plug 27 in for x
y=6(27)-14
y=148
<span>Since it's even, the integral from -7 to -1 is the same as the integral from 1 to 7.
</span><span>think about
x^2
from 0..1,its 1/3
from 0..7 its 7^3/3
from -1..7 its 7^3/3+1/3
</span>
<span>from -7..-1 of x^2 its -1/3+7^3/3 to get this without integrating we just do 7^3/3-1/3 which is the integral from 0..7 minus the integral from 0..1
</span><span>So the integral from 1 to 0 f(x) dx = 5 changes to the integral from 0 to 1 f(x) dx = -5 and you add it to the integral from 0 to 7 which is 1 making -4</span>
Answer:
$360. (I believe so, anyways.)
Step-by-step explanation:
Original Price x Discount % / 100
Discount = 600 × 40/100
24000/100
$600 - $240
Final Price = $360
Answer:
![a = \frac{-1}{3}.](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B-1%7D%7B3%7D.)
Step-by-step explanation:
The equation of line in the form .
y = mx + c
Where m is the slope and c is the y- intercept .
As given
The lines y=3x-1 and y=ax+2 are perpendicular .
Here 3 is slope for equation of line y=3x-1 and a is slope for equation of line
y=ax+2 .
Now by using properties of the perpendicular lines property .
When two lines are perpendicular than slope of one line is negative reciprocal of the other line .
Thus
![a = \frac{-1}{3}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B-1%7D%7B3%7D)
Therefore ![a = \frac{-1}{3}.](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B-1%7D%7B3%7D.)