Answer:
Step-by-step explanation:


case~2

Answer:
y = 2x + 1
Step-by-step explanation:
1. Find the slope; (change in y values)/(change in x values)
Slope = (-5 - 3)/ (-3 - 1) = -8/-4 = 2
2. Find the y-intercept (b) using the slope intercept formula: y = mx + b
m = 2 and using point (1, 3) , solve for "b"
y = mx + b
3 = 2(1) + b
3 = 2 + b
1 = b
3. Write the linear equation: y = 2x + 1
B. All rectangles are parallelograms. <span />
The answer should be 6! all you have to do is plug the numbers into the equation!
it would be like this:
-1^2+3^2+(-1)-3
doing all of that would equal 6!
So Congruent. Two figures are congruent if they have the same shape and size. Two angles are congruent if they have the same measure. Two figures are similar if they have the same shape but not necessarily the same size.
I hope that help u:)