Which number is equivalent to the fraction 18\5
2 answers:
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Answer:
1) The mean calculated for this case is
2)
3)
4) B. An interval estimate gives us a sense of the accuracy of the point estimate whereas a point estimate alone does not.
Because with the confidence interval we know the confidence level of the interval, and the limits for the parameter at some significance level.
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Part 1
In order to calculate the mean and the sample deviation we can use the following formulas:
(a)
(b)
The mean calculated for this case is
The sample deviation calculated
population mean (variable of interest)
n=6 represent the sample size
Part 2
The confidence interval for the mean is given by the following formula:
(1)
So if we have the margin of error 5.4mm we can find the lowr limit like this:
Part 3
Part 4
B. An interval estimate gives us a sense of the accuracy of the point estimate whereas a point estimate alone does not.
Because with the confidence interval we know the confidence level of the interval, and the limits for the parameter at some significance level.
Answer:
1,2 and 4 are conservatives
3 is not conservative
Step-by-step explanation:
We calculate the Curl F
Remember that:
Curl F = <>
1. Curl F = <0,0,5-5> = <0,0,0>
The potential function f so that ∇f=F
f(x,y,z) =
Then F is conservative
2. Curl F = < 0, 0 ,0>
The potential function f so that ∇f=F
f(x,y,z) =
Then F is conservative
3. Curl F = <0 ,0, 10+3xsin(y) - (-cos(y))>
= <0 ,0 , 10 +3xsin(y) + cos(y)<
How the field's divergence is not zero the vector field is not conservative
4. Curl F = <0, 0, 0>
The potential function f so that ∇f=F
f(x,y,z) =
Then F is conservative