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3 years ago

What is negative 1 and three fifths divided by negative two thirds equals?

Mathematics

2 answers:

Rudik [331]3 years ago

6 0

It's visually better to make it an equation.
-1 3/5 ÷ -2/3

The answer is 39/10.

grandymaker [24]3 years ago

5 0

First lets make 1 3/5 into a improper fraction
Next lets multiply 5 * 1 and we get 5
Then lets add 3 + 5 and we get 8
Next lets multiply 3 * 2 and we get 6
Next lets do 8/ 6 * 5
And lastly multiply 6 * 5 to get 30 and simplify.

Answer: 4/15

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No need for explanation

Free_Kalibri [48]

Answer:

Step-by-step explanation:

I'll assume they're vertical angles

5x - 13 = 2x + 14

3x = 27

x = 9

<ABC:

5x - 13

5(9) - 13

8 0

3 years ago

Read 2 more answers

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galben [10]

I don’t know the answer I jus need to answer 2 questions

7 0

3 years ago

If z varies inversely as w, and zequals

quester [9]

Z = 4 , w = 6
z = x , w = 8

Therefore, z = (4*8) / 6
= 32 / 6
= 16/3 = 5.333

4 0

4 years ago

1) What is the equation of a line that is parallel to the line that is given by the equation x = -4?

tester [92]

Not sure its A but use this http://www.mathpapa.com/algebra-calculator.html

8 0

4 years ago

Evaluate exactly without the use of a calculator (remember to rationalize any denominators). a.(cos 60o)(sin 270o) + tan 225o b.

Rom4ik [11]

Given:

The trigonometric expressions are given as,

$\begin{gathered} a)\text{ }(\cos 60\degree)(\sin 270\degree)+\tan 225\degree \\ b)-\tan 240\degree+(cos45\degree)(\sec 135\degree) \end{gathered}$

Explanation:

The given expression can be rewritten as,

$=(\cos 60\degree)(\sin (360\degree-90\degree))+\tan (270\degree-45\degree)\text{ . . . . .(1)}$

Since, from the trigonometric ratios,

$\begin{gathered} \sin (360\degree-90\degree)=-\sin 90\degree \\ \tan (270\degree-45\degree)=\cot 45\degree \end{gathered}$

On plugging the obtained ratios in equation (1),

$=(\cos 60\degree)(-\sin 90\degree)+\cot 45$

Substitute the trigonometric values in the above equation.

$\begin{gathered} =\frac{1}{2}(-1)+1 \\ =-\frac{1}{2}+1 \\ =\frac{1}{2} \end{gathered}$

Hence, the exact value of the expression is 1/2.

The given expression can be rewritten as,

$=-\tan (270\degree-30\degree)+(\cos 45\degree)(\sec (90\degree+45\degree))\text{ . . . ..(2)}$

Since, from the trigonometric ratios,

$\begin{gathered} \tan (270\degree-30\degree)=\cot 30\degree \\ \sec (90\degree+45\degree)=-\csc 45\degree \end{gathered}$

On plugging the obtained ratios in equation (2),

$=-\cot 30\degree+(\cos 45\degree)(-\csc 45)$

Substitute the trigonometric values in the above equation.

$\begin{gathered} =-\sqrt[]{3}+\frac{1}{\sqrt[]{2}}(-\sqrt[]{2}) \\ =-\sqrt[]{3}-1 \end{gathered}$

Hence, the exact value of the expression is -√3-1.

7 0

2 years ago