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arlik [135]
4 years ago
4

Please Help

Mathematics
2 answers:
charle [14.2K]4 years ago
8 0
It's c. I literally just answered it

ra1l [238]4 years ago
4 0

Answer:

Option: C is the correct answer.

\dfrac{h}{4}=\dfrac{12}{5}

Step-by-step explanation:

Clearly from the diagram shown we could see that the angle formed at the base is the same.

Let the angle be theta (θ).

Hence, in the small right angled triangle ΔACB we have:

\tan \theta=\dfrac{AC}{CB}\\\\\tan \theta=\dfrac{4}{5}------(1)

Similarly in the right angled triangle ΔEDB we have:

\tan \theta=\dfrac{ED}{DB}\\\\\tan \theta=\dfrac{h}{12}------(2)

Hence, on equating equation (1) and equation (2) we have:

\dfrac{4}{5}=\dfrac{h}{12}\\\\\dfrac{h}{4}=\dfrac{12}{5}

Hence, option:C is the correct option.

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Skylar invested $3,100 in an account paying an interest rate of 3.3% compounded quarterly. Assuming no deposits or withdrawals a
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13

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​  

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3 years ago
One number is 5 more than twice another and their sum is 23.
icang [17]
<span>y = 2x + 5

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The heights of 10 year old children has a normal probability distribution with mean of 54.6 inches and standard deviation of 5.7
Fofino [41]

Answer:

a) 0.69

The probability that a randomly selected 10-year old child will be more than 51.75 inches tall

P(X>51.75 ) = 0.6915

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

<em>Given mean of the Population = 54.6 inches</em>

<em>Given standard deviation of the Population = 5.7 inches</em>

<em>Let 'X' be the random variable of normal distribution</em>

Let 'X' = 51.75 inches

Z = \frac{x-mean}{S.D} = \frac{51.75-54.6}{5.7} = -0.5

<u><em>Step(ii):</em></u>-

<em>The probability that a randomly selected 10-year old child will be more than 51.75 inches tall</em>

<em>P(X>51.75 ) = P(Z>-0.5)</em>

                  = 1 - P( Z < -0.5)

                 =   1 - (0.5 - A(-0.5))

                =    1 -0.5 + A(-0.5)

               =    0.5 + A(0.5)    (∵A(-0.5)= A(0.5)

              =     0.5 +0.1915

              =  0.6915

<u><em>Conclusion</em></u>:-

<em>The probability that a randomly selected 10-year old child will be more than 51.75 inches tall</em>

<em>P(X>51.75 ) = 0.6915</em>

5 0
3 years ago
Need help understanding how to solve
qwelly [4]

For the two figures to be similar, the missing length must be 30.

<h3 /><h3>What is the missing length?</h3>

For the two figures to be similar, the dimension of each figures must be proportional to each other.

Let the missing length be x.

Hence,

x/25 = 24/20

We cross multiply

x × 20 = 24 × 25

x × 20 = 600

x = 600/20

x = 30

Therefore, for the two figures to be similar, the missing length must be 30.

Learn more about similarity and congruence here: brainly.com/question/7888063

#SPJ1

4 0
2 years ago
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