The pool can hold 65.84 ft³ of water
<u>Explanation:</u>
Given:
Shape of pool = octagonal
Base area of the pool = 22 ft²
Depth of the pool = 3 feet
Volume, V = ?
We know:
Area of octagon = 2 ( 1 + √2) a²
22 ft² = 2 ( 1 + √2 ) a²
a² = 
a² = 4.55
a = 2.132 ft
Side length of the octagon is 2.132 ft
We know:
Volume of octagon = 
Therefore, the pool can hold 65.84 ft³ of water
11/25
88/1000
Divide each by 8
11. Times 8
125 times 8
*You could use a calculator
50 times 50 times 50 times 20 equals <span>2500000</span>
Your answer is <em>2500000</em>
Answer:
can you help me
Step-by-step explanation:
Answer:
V = 1071.79 yd^3
Step-by-step explanation:
The volume of a cone is
V = 1/3 pi r^2 h where r is the radius and h is the height
We are given a diameter of 16 so the radius is 1/2 of the diameter or 8
The height is 16
V = 1/3 ( 3.14) (8)^2 ( 16)
V = 1071.78666 yd^3
Rounding to the nearest hundredth
V = 1071.79 yd^3
